Integral P(r) Normalization: Find Constant

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Homework Help Overview

The discussion revolves around the normalization of a function p(r) that is proportional to (1/r)Exp(-r/R), where R represents the proton radius. The original poster is attempting to find the normalization constant by integrating this function over a specified range.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to normalize the function by setting up an integral from infinity to negative infinity but expresses confusion regarding the integration process, particularly due to perceived discontinuities. Some participants suggest that the integration limits may need to be reconsidered, specifically from r=0 to r=∞.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the integration limits and the nature of the function. Some guidance has been offered regarding the correct range for integration, but no consensus has been reached on the normalization process itself.

Contextual Notes

There is an indication that the original poster may be misunderstanding the appropriate limits for the integral, which could affect the normalization process. The mention of discontinuities suggests that there are complexities in the function that need to be addressed.

alfredbester
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p(r) is proportional too (1/r)Exp(-r/R). r is the variable.

I'm trying to normalise this function (R is proton radius), so I'm trying to get the integral between infinity and -infinity = 1 so I can find the normalisation constant. I don't know how to do this integral I've tried by parts but it seems there are discontuinities. I'm probably missing something obvious, can sombody point me on the right track?
 
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:wink: Non-elementary solution.

http://mathworld.wolfram.com/ExponentialIntegral.html"
 
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Thanks, I can't see how to normalise this function however.
 
Probably you're integrating from [itex]r=0[/itex] to [itex]r=\infty[/itex], not over the whole range of r.
 

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