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Integrate (5x+2)dx/(x-2) from 0->1

  1. Dec 8, 2007 #1
    i am trying to integrate Integrate (5x+2)dx/(x-2) from 0 to 1. i have tried splitting the equation up into (5x)/(x-2) + (2)/(x-2)
    i have tried every U substitution i can think of but i cant figure out how to do it.
     
  2. jcsd
  3. Dec 8, 2007 #2

    cristo

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    Which substitutions have you tried? What about u=x-2?

    Note in future that you should post these sort of questions in the suitable homework forum, and no the technical forums.
     
  4. Dec 8, 2007 #3
    sorry about that
     
  5. Dec 8, 2007 #4
    integration by parts

    u=(5x+2) dv=(1/(x-2))

    how would that work?
     
    Last edited: Dec 8, 2007
  6. Dec 8, 2007 #5
    The u substitution suggested above completely kills the problem ice. The integral becomes a linear polynomial in u over u, and then can be broken into pieces and integrated by the power rule.
     
  7. Dec 8, 2007 #6

    cristo

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    Let u=x-2, then du=dx and x=u+2. This converts the integral into [tex]\int\frac{5(u+2)du}{u}=\int\left[5+\frac{10}{u}\right]du[/tex]
     
  8. Dec 8, 2007 #7
    feck im dumb
     
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