What is the intuition behind integrating with respect to another function?

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Discussion Overview

The discussion revolves around the intuition behind integrating a function with respect to another function, specifically in the context of the Riemann–Stieltjes integral and its implications when the second function may not be differentiable or continuous. The scope includes theoretical exploration and conceptual clarification.

Discussion Character

  • Exploratory, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant suggests that integrating a function with respect to another can be interpreted mathematically using the chain rule, leading to a representation involving the slope of the second function.
  • Another participant raises the question of the implications when the second function is not differentiable or continuous, indicating a potential interest in the Riemann–Stieltjes integral.
  • A different viewpoint mentions the use of stochastic calculus, specifically Ito integrals, as a method to address cases where the second function lacks differentiability.
  • One participant proposes that integrating with respect to another function serves as a way to weight the domain of integration.

Areas of Agreement / Disagreement

Participants express differing views on the intuition behind the integral, with some focusing on mathematical interpretations while others emphasize the conceptual understanding, indicating that the discussion remains unresolved.

Contextual Notes

The discussion highlights limitations regarding the assumptions about the continuity and differentiability of the second function, as well as the implications of these properties on the interpretation of the integral.

Apteronotus
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When we integrate a function f(t) with respect to t, we are finding the area under the curve f. Intuitively, this is very clear.

What is the intuition behind integrating a function with respect to another function?
ex.
<br /> \int f(t)dg<br />
where g is itself a function of t?
 
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I'm not sure there is an easy intuitive answer, beyond interpreting it mathematically.
Since g is a function of t, you can apply the chain rule to give

\int f(t)d[g(t)]=\int f(t)\frac{d[g(t)]}{dt}dt=\int f(t)\.{g}(t) dt

So you are finding the area under another curve that equals the first function weighted by the slope of the second.
 
What if g is not differentiable? In fact, the most interesting case is when g is not even continuous. Look up the Riemann–Stieltjes integral
 
Thanks for your attempt Marcus.

l'Hôpital said:
What if g is not differentiable? In fact, the most interesting case is when g is not even continuous. Look up the Riemann–Stieltjes integral

l'Hopital, I suppose if g is not differentiable then the equation can still be solved using stochastic calculus (ie. Ito integrals).
But my question has more to do with trying to understand what the integral represents, rather than a way of solving it.
 
it's a way to weight the domain.
 

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