Integration and population dynamics?

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SUMMARY

The discussion focuses on calculating the increase in a mosquito population in a lake resort area during a hot wet summer, modeled by the differential equation \( \frac{dP}{dt} = 2200 + 10e^{0.8t} \). The participants confirm that to find the population increase between the fifth and ninth weeks, one must evaluate the definite integral \( N = P(9) - P(5) = \int_5^9 (2200 + 10e^{0.8t}) \, dt \). The final calculated increase in the mosquito population is 24,860, confirming the correct application of the Fundamental Theorem of Calculus (FTOC).

PREREQUISITES
  • Understanding of differential equations and their applications
  • Familiarity with the Fundamental Theorem of Calculus (FTOC)
  • Ability to perform definite integrals
  • Basic knowledge of exponential functions
NEXT STEPS
  • Study the Fundamental Theorem of Calculus in detail
  • Practice solving differential equations using integration techniques
  • Explore applications of exponential growth models in population dynamics
  • Learn about numerical methods for approximating integrals
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Students and educators in mathematics, particularly those studying calculus and differential equations, as well as professionals in fields related to population dynamics and ecological modeling.

ineedhelpnow
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can someone explain this problem step by step (not a homework problem, just an example i found and i want to see how its done).

a hot wet summer is causing a mosquito population explosion in a lake resort area. the number of mosquitoes is increasing at an estimated rate of 2200+10e^(0.8t) per week (t is in weeks). by how much does the mosquito population increase between the fifth and ninth weeks of summer.
 
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We are given:

$$\d{P}{t}$$

and asked to find:

$$N=P(9)-P(5)$$

Can you see how to use the anti-derivative form of the FTOC here?
 
no do you mind explaining?
 
If you are given $dP$ what operation can you use to find $P$? If you want to find $P(a)-P(b)$ what operation would you use from $dP$? Something should come to mind.
 
this is probably wrong but do i just integrate 2200+10e^0.8t from 5 to 9?

@Jameson this sounds super weird but I get a happy feeling whenever i see your username and your profile picture. its' so cool man, i swear. :D
 
ineedhelpnow said:
this is probably wrong but do i just integrate 2200+10e^0.8t from 5 to 9?

Let's take a look:

$$P(9)-P(5)=\int_5^9\,dP=\int_5^9\d{P}{t}\,dt$$

Yep, looks good to me. :D
 
soooo...24860? does that sound right?
 
Yes, since a population is discrete rather than continuous we would use:

$$N=\left\lfloor \int_5^9 2200+10e^{0.8t}\,dt \right\rceil=24860$$
 
ok thanks.
 

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