MHB Integration and population dynamics?

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A hot, wet summer is causing a significant increase in the mosquito population at a lake resort, with the growth rate modeled by the equation 2200 + 10e^(0.8t) per week. To find the population increase from the fifth to the ninth week, the integral of the growth rate from 5 to 9 is calculated. The operation involves using the Fundamental Theorem of Calculus to determine the difference in population, represented as N = P(9) - P(5). The integration yields a population increase of approximately 24,860 mosquitoes. This example illustrates the application of calculus in understanding population dynamics.
ineedhelpnow
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can someone explain this problem step by step (not a homework problem, just an example i found and i want to see how its done).

a hot wet summer is causing a mosquito population explosion in a lake resort area. the number of mosquitoes is increasing at an estimated rate of 2200+10e^(0.8t) per week (t is in weeks). by how much does the mosquito population increase between the fifth and ninth weeks of summer.
 
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We are given:

$$\d{P}{t}$$

and asked to find:

$$N=P(9)-P(5)$$

Can you see how to use the anti-derivative form of the FTOC here?
 
no do you mind explaining?
 
If you are given $dP$ what operation can you use to find $P$? If you want to find $P(a)-P(b)$ what operation would you use from $dP$? Something should come to mind.
 
this is probably wrong but do i just integrate 2200+10e^0.8t from 5 to 9?

@Jameson this sounds super weird but I get a happy feeling whenever i see your username and your profile picture. its' so cool man, i swear. :D
 
ineedhelpnow said:
this is probably wrong but do i just integrate 2200+10e^0.8t from 5 to 9?

Let's take a look:

$$P(9)-P(5)=\int_5^9\,dP=\int_5^9\d{P}{t}\,dt$$

Yep, looks good to me. :D
 
soooo...24860? does that sound right?
 
Yes, since a population is discrete rather than continuous we would use:

$$N=\left\lfloor \int_5^9 2200+10e^{0.8t}\,dt \right\rceil=24860$$
 
ok thanks.
 

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