Interaction picture - time evolution operator

  • #1
20
0

Main Question or Discussion Point

Hey all,

I got some question referring to the interaction picture. For example:

I have the Hamiltonian ##H=sum_k w_k b_k^\dagger b_k + V(t)=H1+V(t)##

When I would now have a time evolution operator:

##T exp(-i * int(H+V))##.

(where T is the time ordering operator)

How can I transform it into the interaction picture?

Do I have to calculate:

##exp[i H(1)t]T exp(-i int(H+V))exp[-i H(1)t]##

This is nearly impossible, isn't it?

Best

(is it possible to use latex here?)
 
Last edited by a moderator:

Answers and Replies

  • #2
11,348
4,818
I adjusted your post using the double # around your latex expressions and they look a lot better. You can do the same.
 

Related Threads for: Interaction picture - time evolution operator

  • Last Post
Replies
8
Views
3K
  • Last Post
Replies
1
Views
627
  • Last Post
Replies
1
Views
256
  • Last Post
Replies
7
Views
2K
Replies
1
Views
762
Replies
2
Views
886
Replies
39
Views
992
Replies
3
Views
3K
Top