Interchange Between Union and Intersection: Am I Correct?

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The discussion centers on the interchangeability of union and intersection in set operations, specifically the expression \cup_{q < t} \cap_{s > q} A_{s} = \cap_{s PREREQUISITES

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wayneckm
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Hello all,


I have the following question regarding the interchange between union and intersection.

\cup_{q &lt; t} \cap_{s &gt; q} A_{s} = \cap_{s&lt;t} \cup_{q&lt;s} A_{q} = \cup_{q &lt; t} A_{q}

Am I correct? Also, can anyone provide me some more resources regarding this kind of interchange in set operation or change of variable technique?

Thanks.


Wayne
 
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Off the top of my head, it doesn't look correct.

Suppose Ai is empty for all i>100. Then \cap_{s&gt;q}A_s will be empty for all q, and the union of these will be empty. So lhs is empty.

But rhs, being just a union of As, will not necessarily be empty.
 

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