Perhaps it may be easier if i post the question that has sparked my confusion:
A science student connects a dynamic loudspeaker to a low voltage AC power pack in an Australian school. The loudspeaker sends sound waves directly towards a concrete wall 3.0 metres away. Take 340 ms-1 as the speed of sound. Wavelength = 6.8m
How many softspots are there located between the wall and speaker? Explain.
Okay, a soft spot is formed due to the presence of a node. When sound is emitted from the speaker it is reflected from the wall and intefers with the wave emitted from the speaker. This produces a standing wave.
That is as far as i can get, i do not understand how to find how many nodes there would be. My understand of a node is when the path difference of two sound waves in phase is wavelength/2, 3wavelength/2, etc. If that's the case then the first soft spot should occur 3.4m from the wall, therefor no soft spots formed. However the answer states that there should be 1 soft spot?