Interference from Thin Films: What Happens to Wavelengths in Different Media?

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SUMMARY

The discussion centers on the behavior of light wavelengths as they pass through different media, specifically oil and glass. The index of refraction for oil is 1.45 and for glass is 1.50. The conclusion drawn is that the wavelength of light in oil is greater than that in glass due to the relationship defined by the equation x_n_ = x/n_2_, where x_n_ represents the wavelength in the medium, x is the wavelength in air, and n_2_ is the index of refraction of the medium. Therefore, the correct answer to the homework question is A) greater than.

PREREQUISITES
  • Understanding of light wave properties and behavior in different media
  • Familiarity with the concept of index of refraction
  • Knowledge of wavelength calculations in various substances
  • Basic grasp of optics equations, particularly 2*n_oil*L = m*x
NEXT STEPS
  • Research the relationship between wavelength and index of refraction in different materials
  • Learn about the effects of thin film interference on light waves
  • Explore the calculation of wavelengths in various media using Snell's Law
  • Investigate practical applications of thin films in optics and coatings
USEFUL FOR

This discussion is beneficial for students studying optics, physics educators, and anyone interested in understanding the principles of light behavior in different media, particularly in relation to thin films.

baseballer10p
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Homework Statement


Light of wavelength x, in air, is incident in air on a film of oil with index of refraction n_oil = 1.45. The film of oil has thickness L, and is spread on glass with an index of refraction n_glass = 1.50.
The wavelength of the light in oil will be _____ than the wavelength of the light in glass.
A) greater than B) equal to C)less than
physics-1.jpg


Homework Equations


2*n_oil*L = m*x

The Attempt at a Solution


I know the answer is A, but I can't figure out why. Can someone help me out on this? Thanks.
 
Last edited:
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Hi baseballer10p,

How is the wavelength of light in a substance related to its wavelength in air (assuming that we say the index of refraction of air is 1)?

Once you have that you can calculate both the wavelength in oil and glass separately and see which one is larger.
 
Ok, I got the answer, but I want to make sure.

Is it x_n_ = x/n_2_

where x_n_ is the wavelength in the oil and x is the wavelength in air? n_2_ is the index of refraction of the oil or glass correct?

Thanks, by the way.
 
Last edited:
Looks good; you can then find the wavelength of the light in the oil and the glass.
 

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