A problem involving thin film interference

In summary, when light travels from a medium with a lower refractive index to one with a higher refractive index, the reflected light undergoes a ##\frac{\lambda}{2}## phase change. This happens at both the air-plate and plate-glass interfaces, causing the phase changes to cancel each other out. The condition for constructive interference in this case is ##2t=m\lambda_{plate}\Leftrightarrow 2t=m\frac{\lambda}{n_F}\Leftrightarrow t=\frac{m\lambda}{2n_F}##, where ##t## is the thickness of the plate. For the minimum (non-zero) thickness, we have ##t=\frac{\lambda}{2n_F
  • #1
lorenz0
148
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Homework Statement
A blue (##\lambda=450nm##) beam of light hits a glass plate with ##n_g=1.5##. Calculate the minimum thickness that a plate with refractive index ##n_F=1.33##, that must be placed between the air and the glass to produce the maximum intensity reflected in the blue, should have. How much would this thickness have to be if the light was coming from the glass towards the air?
Relevant Equations
##\lambda_{medium}=\frac{\lambda}{n_{medium}}##
I know that every time that light goes from traveling through a medium with lower refractive index to one with a higher refractive index the reflected light undergoes a ##\frac{\lambda}{2}## phase change. Since this happens both at the air-plate and plate-glass interfaces we have that the phase changes cancel each other out and the condition for constructive interference is (where ##t## denotes the thickness of the plate): ##2t=m \lambda_{plate}\Leftrightarrow 2t=m\frac{\lambda}{n_F}\Leftrightarrow t=\frac{m\lambda}{2n_F}## so the minimum (non-zero) thickness is ##t=\frac{\lambda}{2n_F}.##

In the second scenario the situation is reversed and there is no ##\frac{\lambda}{2}## phase change for both the glass-plate interface and the plate-air interface and so the condition for constructive interference again reads ##2t=m \lambda_{plate}## and we get the same result as before.

Is this correct? I still have to fully grasp this phenomenon and I would like to have feedback on the way I have reasoned about this problem, thanks.
 
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  • #2
Your reasoning is correct.
 
  • Like
Likes lorenz0 and Charles Link
  • #3
kuruman said:
Your reasoning is correct.
Thanks!
 

1. What is thin film interference?

Thin film interference is a phenomenon that occurs when light waves reflect off of the top and bottom surfaces of a thin film, creating interference patterns. This can result in the film appearing to have different colors or patterns depending on the thickness of the film and the wavelength of the light.

2. How does thin film interference work?

Thin film interference works by the superposition of light waves. When light waves reflect off of the top and bottom surfaces of a thin film, they can either constructively or destructively interfere with each other, resulting in different colors or patterns.

3. What causes thin film interference?

Thin film interference is caused by the difference in the refractive index between the film and the surrounding medium. When light waves enter the film, they slow down and change direction, leading to the interference patterns.

4. What are some real-life applications of thin film interference?

Thin film interference has many practical applications, such as in anti-reflective coatings for glasses and camera lenses, in the production of colorful soap bubbles, and in the creation of holograms and other optical devices.

5. How is thin film interference used in scientific research?

Scientists use thin film interference to study the properties of materials, such as their refractive index and thickness. It is also used in the production of thin films for various technologies, such as solar cells and touchscreens.

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