Interpretation of an impulse graph

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Homework Help Overview

The discussion revolves around interpreting an impulse graph related to the motion of a mass, specifically analyzing its velocity, acceleration, and distance traveled over time intervals. The problem is situated within the context of dynamics and kinematics.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of the graph's features, such as inflection points and the relationship between acceleration and velocity. There is a focus on why certain answers can be ruled out based on the graph's behavior.

Discussion Status

Participants are actively questioning the validity of specific answer choices and clarifying the relationship between acceleration and velocity. Some guidance has been offered regarding the interpretation of acceleration and its effect on velocity, but no consensus has been reached on all points of confusion.

Contextual Notes

There is an emphasis on understanding the implications of the graph's features, particularly regarding the points of maximum acceleration and deceleration, as well as the definitions of velocity and acceleration. Participants express frustration over the complexity of the problem.

lovelyrwwr
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Which of the following is true if the mass is at rest at t=0 ?
A. Velocity of the mass is decreasing btwn 10 and 20 seconds.
B. The accel. of the mass is constant between 0 and 10 seconds
C. At 40 seconds the mass is stationary.
D. The distance trsveled by the mass bten 0 and 10 seconds is equal to that traveled btwn 10 and 20 seconds.

The answer is C. I understand why I can rule out answer B. But I do not see why A and D are not true.

From the graph, I see that force decreases during 10 < t < 20 seconds. Thus accel gets smaller but is still positive, which means that velocity should still be increasing. However what I do not understand is what the inflection point at t=10 (and t=30 for that matter) represents...I mean between 0-20 seconds, velocity is always increasing (according to the solution, but then what does this inflection point at t=10 seconds represent?

This problem is driving me insane, please help! :)
 
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lovelyrwwr said:
View attachment 62919
Which of the following is true if the mass is at rest at t=0 ?
A. Velocity of the mass is decreasing btwn 10 and 20 seconds.
B. The accel. of the mass is constant between 0 and 10 seconds
C. At 40 seconds the mass is stationary.
D. The distance trsveled by the mass bten 0 and 10 seconds is equal to that traveled btwn 10 and 20 seconds.

The answer is C. I understand why I can rule out answer B. But I do not see why A and D are not true.

From the graph, I see that force decreases during 10 < t < 20 seconds. Thus accel gets smaller but is still positive, which means that velocity should still be increasing. However what I do not understand is what the inflection point at t=10 (and t=30 for that matter) represents...I mean between 0-20 seconds, velocity is always increasing (according to the solution, but then what does this inflection point at t=10 seconds represent?

This problem is driving me insane, please help! :)

From what you've just said, you can already rule out A. The points at x=10 and x=30 are just the points of maximum acceleration and deceleration respectively. Now you just have to rule out D. I'm not sure what's driving you insane.
 
So btwn t = 0 and 10 seconds the mass is accelerating, right? And from 10 to 20 sec it is still accelerating but acceleration is declining...so shouldn't answer A be true?
 
lovelyrwwr said:
So btwn t = 0 and 10 seconds the mass is accelerating, right? And from 10 to 20 sec it is still accelerating but acceleration is declining...so shouldn't answer A be true?

If it's still accelerating that means velocity is still increasing, just more slowly. Declining acceleration doesn't mean that the velocity is decreasing. Just as you've already said. Acceleration and velocity are two different things.
 
Wow I am such a dope! Thanks for all of ur help! :)))))
 

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