Find the distance traveled on the velocity-time graph

  • Thread starter chwala
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  • #1
chwala
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Homework Statement:
part b. find the distance travelled in the first ##50## seconds
Relevant Equations:
kinematics
1613563411544.png


now this is my approach, my interest in on part b
distance travelled= area under the graph between time ##t=0## and ##t=50##,
area = ##0.5(40+20)10+ (20 × 40) + 0.5(40+20)10+ 0.5×10×20##
Area= ##300+800+300+100=1500m##
now textbook says i am wrong, where have i made a mistake?
 

Answers and Replies

  • #2
chwala
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aaaargh i have seen the mistake...
 
  • #3
chwala
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area = ##0.5(50+20)10+ (20 × 50) + 0.5(50+25)10+ 0.5×10×25##
Area= ##350+1000+375+125=1850m##
 

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