Intersecting Lines to Solve 2sinx + \sqrt{3} = 0

[Imperil]

a) Use the special triangles and the CAST rule to solve the equation 2sinx + \sqrt{3} = 0 for the domain interval 0 \leq x \geq 360.

b) What feature of the graph, in the form y = asinx + b, would show the solutions?


My Answers:

a) sinx = -\sqrt{3}/2
x = -60 degrees

180 + 60 = 240 degrees
360 - 60 = 300 degrees

b) Can anybody give me a clue as to what this is asking? I have absolutely no idea :(

 

[Mark44]

For b, think about where the graph of y = 2sinx + sqrt(3) crosses the x-axis. I think that's what the problem is getting at.

 

[Imperil]

For b, think about where the graph of y = 2sinx + sqrt(3) crosses the x-axis. I think that's what the problem is getting at.

This is what I was thinking of as the graph will cross x at 4Pi/3 and 5Pi/3, so I was thinking that the feature to show the solution would be the x-intercepts.

Is this correct? I originally thought this but then was confused by the words "feature of the graph"

 

[Mark44]

An x-intercept is a feature of a graph. Again, I think this is what the question is getting at.