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Interval for a normal distribution

  1. Jan 18, 2014 #1
    1. The problem statement, all variables and given/known data

    A machine fills cereal boxes, normally distributed, with standard deviation of .1 oz. What amount setting should the machine be set to if only 1% of the boxes can have less than 16oz of cereal?

    2. Relevant equations

    3. The attempt at a solution

    I am thinking that I just manipulate the confidence interval for a normal distribution. So x - 2.33(σ) = 16, with 2.33 being the z-score for 99%. My amount would then be 16.233. Am I way off? Thanks
  2. jcsd
  3. Jan 18, 2014 #2

    Ray Vickson

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    Your reasoning and your answer are correct.
    Last edited: Jan 18, 2014
  4. Jan 18, 2014 #3
    Thanks, Dr. Vickson
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