Is 2017^4+4^{2017} a Prime Number?

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The expression $2017^4 + 4^{2017}$ is not a prime number. The discussion highlights that both participants contributed to the analysis of this expression, confirming that it can be factored. The solution provided by one participant, while not directly copied from another, indicates a collaborative effort to explore the properties of this mathematical expression.

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Is $2017^4+4^{2017}$ a prime?
 
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anemone said:
Is $2017^4+4^{2017}$ a prime?

$$\begin{align*}2017^4+4^{2017}&=(2017^2)^2+(2^{2017})^2 \\
&=(2017^2+2^{2017})^2-2\cdot2017^2\cdot2^{2017} \\
&=(2017^2+2^{2017})^2-2017^2\cdot2^{2018} \\
&=(2017^2+2^{2017}-2017\cdot2^{1009})(2017^2+2^{2017}+2017\cdot2^{1009})\end{align*}$$

$$Q.E.D.$$
 
anemone said:
Is $2017^4+4^{2017}$ a prime?

$2017^4 + 4^{2017}= (2017^2)^2 + (2^{2017})^2 + 2 * 2017^2 * 2^ {2017} - 2017^2 * ( 2^{1009})^2$
= $(2017^2+ 2^{2017})^2 - (2017 * 2^{1009})^2 $
= $(2017^2+ 2^{2017}+ 2017 * 2^{1009}) (2017^2+ 2^{2017}- 2017 * 2^{1009})$

it not a prime

edit: I posted my solution dispite the fact that gregs' solution came but I did not copy it
 
Thanks both for participating! :D
 

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