- #1
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f(x^2*2016x) = f(x)x+2016
Then f(2017) = ?
Then f(2017) = ?
The domain of the function is all real numbers except for 2016, since the expression x^2-2016x
would result in division by zero.
No, the function is not one-to-one because for two different inputs, x
and y
, the function can result in the same output f(x) = f(y)
if x^2-2016x = y^2-2016y
.
The range of the function is all real numbers, as the function can take on any value depending on the input x
.
Yes, the function is undefined at x = 2016
, as mentioned in the domain.
Yes, this function can be rewritten as f(x) = x^2-2016x
, since f(x)
is equal to both sides of the original equation.