Is a pure state a kind of mixed states?

Click For Summary
SUMMARY

A pure state is not classified as a mixed state in quantum mechanics, as pure states are represented by projection operators while mixed states are described by statistical operators. The quantum jump by observation applies to both pure and mixed states, highlighting the significance of recording observed values. Key references include Matteo G. A. Paris's tutorial on quantum states and Paul Busch's work on quantum measurement limitations, which provide foundational insights into the representation of quantum states and the implications of observation in quantum mechanics.

PREREQUISITES
  • Understanding of density operators in quantum mechanics
  • Familiarity with projection operators and their role in representing pure states
  • Knowledge of von Neumann measurement theory
  • Basic concepts of Hilbert space and quantum state representation
NEXT STEPS
  • Study the formalism of density operators in quantum mechanics
  • Explore the implications of quantum measurement as discussed in Paul Busch's paper
  • Learn about the role of projection operators in Hilbert space
  • Investigate the significance of recording observations in quantum mechanics
USEFUL FOR

Quantum physicists, researchers in quantum mechanics, and students studying the foundations of quantum theory will benefit from this discussion.

sweet springs
Messages
1,223
Reaction score
75
Hi.
1. Does a pure state belong to mixed states

\hat{\rho}=\sum_k p_k|\psi_k><\psi_k| where ##p_k=1## for k=i and otherwise 0 ?
2. Does quantum jump by observation work for both mixed and pure states ?
Your teachings will be appreciated.
 
Physics news on Phys.org
If we use density operators to represent states, both pure states and mixed states can be represented in the same formalism. In the usual terminology, pure states are not mixed states.

The quantum jump by observation works for both pure and mixed states.

https://arxiv.org/abs/1110.6815
The modern tools of quantum mechanics (A tutorial on quantum states, measurements, and operations)
Matteo G. A. Paris
See postulates II.4 and II.5 on p9

https://arxiv.org/abs/0706.3526
"No Information Without Disturbance": Quantum Limitations of Measurement
Paul Busch
See Eq 3 and 4
 
  • Like
Likes   Reactions: vanhees71
I will read them fully. Thanks a lot.
atyy said:
See postulates II.4 and II.5 on p9
I thought pure states always take place after observation of both pure and mixed states. II5 tells us that mixed states appear if we do not record observed values. It is very interesting that recording or memory matters physics.
 
You prepare a pure state, e.g., by performing a simultaneous von-Neumann-filter measurement of a complete set of observables, and indeed states are most conveniently described by statistical operators, which are of the form as you wrote. They are self-adjoint positive semi-definite operators with trace 1. The pure states are exactly the projection operators, where exactly one of the ##p_k## is 1 and thus all others 0.

One cannot overstress the importance of the fact that pure states are NOT represented by unit vectors in Hilbert space but by the corresponding projection operators or, equivalently, unit rays in Hilbert space. In other words overall phase factors are not physical, and this has a lot of important consequences. One of the most important is that you can have half-integer spin and fermions. Our entire existence as living beings rests on the existence of fermions!
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 65 ·
3
Replies
65
Views
9K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 62 ·
3
Replies
62
Views
10K