Is an Non-Zero Coefficient in a Polynomial a Zero Divisor in R[x]?

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Discussion Overview

The discussion revolves around the question of whether a non-zero coefficient in a polynomial can be classified as a zero divisor in the polynomial ring R[x], given that the polynomial itself is a zero divisor in that ring. The scope includes mathematical reasoning and proof exploration.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant proposes that if a polynomial with a non-zero leading coefficient is a zero divisor in R[x], then the leading coefficient itself must also be a zero divisor in R.
  • Another participant expresses support for this reasoning but questions what additional proof is needed to solidify the argument.
  • A different participant expresses uncertainty about the validity of the initial claim.
  • Another participant confirms the legitimacy of the argument but advises caution regarding notation.

Areas of Agreement / Disagreement

Participants generally agree on the validity of the initial reasoning, but there is uncertainty regarding the completeness of the proof and notation used.

Contextual Notes

Participants have not resolved the details of the proof or clarified the implications of notation in their arguments.

chuy52506
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Let R be a commutative ring. If an doesn't equal 0 and
a0+a1x+a2x^2+...+anx^n is a zero divisor in R[x], prove that an is a zero divisor in R.


What I did was say if the polynomial is a zero divisor in R[x] then let that polynomial equal p(x) and any other polynomial be q(x) with coefficients b0,b1,...,bm, then p(x)*q(x)=0. And the leading coefficient and degree will be an*bm*x^(n+m) which will be a zero divisor in R. Therefore an will be a zero divisor. However I don't know what to say to show this? is it correct?
 
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What you said sounds good! What more do you want to show??
 
Haha I'm not sure if it's legit?
 
Yes,, it's legit, but you'd have to watch your notations!
 

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