I Is it possible for a BBO crystal to produce an interference pattern?

Click For Summary
The discussion centers on the role of the BBO crystal in the quantum eraser experiment, particularly its ability to produce interference patterns. When a laser beam passes through a double-slit and hits the BBO crystal, it generates entangled photon pairs through spontaneous down-conversion. Each emitted photon carries half the energy and double the wavelength of the original photon, and the question arises whether these entangled beams can show interference patterns on screens. The conversation references studies confirming that single photons can indeed exhibit interference, emphasizing the coherence of the signal photon despite being unpolarized. The implications of this setup challenge assumptions about the behavior of light and the conditions necessary for preserving interference patterns.
Herbascious J
Messages
165
Reaction score
7
TL;DR
Is it possible under any circumstances for a BBO crystal placed after a double slit to produce an interference pattern?
This question originated under a separate thread (see below) in an attempt to better understand what is happening with the quantum eraser experiment. Specifically, it seems that the BBO crystal which splits the photon beam after the double slit is critical in how the experiment is setup.

Regarding the crystal, If a laser is directed at a BBO crystal, it is my understanding that the majority of photons will pass straight through the crystal. However, a small minority of photons will under go "spontaneous down-conversion", meaning that a single photon will split into two, less energetic photons, that are identical and entangled. These two photons will be emitted from the crytsal at angles moving away from each other in specific directions. The assumption is that these photons will each have exactly half the energy of the parent photon and therefore have exactly double the wavelength. It is these two entangled split beams of light which are the subject of the quantum eraser experiment. This question is only about the behavior of the BBO crystal. The question is as follows...

Imagine a laser passes through a double-slit, immediately after which a BBO crystal is placed. Two entangled beams of light emit out at angles from the crystal. Each of these beams of light have light coming from both slits. Each beam is directed onto a simple screen so the light and it's pattern can be displayed, the assumption being, each screen shows an identical pattern, one a copy of the other. Keep in mind no which way information is known anywhere in the equipment. Do the screens show interference? Are there any circumstances where the BBO crystal can emmit light that shows an interference pattern that is preserved? What assumptions in this thought experiment are possibly misleading (eg. the beams may not be exactly double the wavelength of the parent beam in a discreet way).

https://www.physicsforums.com/threa...ff-sensor-to-bring-back-interference.1055858/
 
Last edited:
Physics news on Phys.org
I think the single photons in the pair can show interference patterns, as confirmed, e.g., in the paper by Walborn et al on their realization of the delayed choice quantum eraser:

https://arxiv.org/abs/quant-ph/0106078

The final paper is better formatted (particularly concerning the figures):

https://doi.org/10.1103/PhysRevA.65.033818

It's discussed there on page 2+3 (Eq. (7)). That's, of course, for the setup without the QWPs in the slits.

It's also physically plausible: Concerning its momentum state the signal photon is pretty well coherent, i.e., has a pretty small width in momentum and thus can interfer. It's of course completely unpolarized, but this doesn't affect the diffraction interference pattern in the double-slit experiment.

For a didactical presentation (slides of my habilitation colloquium), see

https://itp.uni-frankfurt.de/~hees/publ/habil-coll-talk-en.pdf
 
  • Like
Likes Herbascious J
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

Similar threads

Replies
24
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
28
Views
2K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K