Is it possible to calculate 100,000 MT nuclear blast radius?

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SUMMARY

The discussion focuses on calculating the blast radius of a 100,000 MT nuclear explosion, emphasizing that the blast radius is not a constant and varies based on several factors. Key considerations include the definitions of "blast radius" related to overpressure, temperature, and destruction, all of which depend on the height of the explosion. Tools such as the asteroid impact calculator and nuclear explosion simulators are referenced to estimate the areas affected by varying yields, indicating a scaling factor of approximately 9 for area with each tenfold increase in yield. The analysis concludes that for a 100,000 MT explosion, the expected area of total destruction could reach 25 million km², translating to a radius of about 2800 km under ideal conditions.

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  • Understanding of nuclear explosion mechanics
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mkarger
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Really, what I'm wondering is if the blast radius is a constant given an increase in output. I assume it is not. So I'm really at a loss as to how to calculate such a massive value.

The scenario is the explosion occurs at sea level on a flat desert plane.

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What do you define as "blast radius"?
Radius of some specific overpressure?
Radius of some specific temperature?
Radius of some specific destruction?
In addition, all three will depend on the height of the explosion.
 
Last edited:
mfb said:
What do you define as "blast radius"?
Radius of some specific overpressure?
Radius of some specific temperature?
Radius of some specific destruction?
In addition, all three will depend on the height of the explosion.

I'm thinking of the radius within which there is "total destruction" of any objects that are not very heavily reinforced.
 
http://www.nucleardarkness.org/nuclear/nuclearexplosionsimulator/
Does not allow to detonate nukes above 2 MT, but I did some scaling guesswork:

"Certain Mass Fires" radius:
2 MT: 821 km^2
1 MT: 417 km^2
0,2 MT: 88 km^2
0,02 MT: 10 km^2
0,002 MT: 1,3 km^2

Looks like a factor of ~9 for the area for a factor of 10 in weapon yield. If that does not change, I would expect an area of 25*10^6 km^2 or a radius of 2800 km for an explosion of 10^5 MT. However, this would need a nearly flat explosion, which is a bit unrealistic for such a high yield. Multiple bombs at different places could give that effect, of course.Another tool, here for the shock wave:
5 psi overpressure: "Complete destruction of ordinary houses, and moderate to severe damage to reinforced concrete structures, will occur within this ring." (does not take heat into account)

100MT: 20.99 km radius
20MT: 12.28 km
2MT: 5.7 km (102km^2)
0,2MT: 2.64 km
0,02MT: 1.23 km
That corresponds to a factor of 2.15 in radius or 4.64 in area for a factor of 10 in yield. As ##10^{1/3}=2.154## and the shock wave is spherical, that looks reasonable.
Scaled to 10^5 MT:
100MT: 208 km radiusA third tool shows effects of the shock wave and heat at the same time, and indicates that indeed the burned area expands quicker with weapon yield than the shockwave. And it shows the difference between an explosion on ground and in the air.
 
I expect that for bombs over a few tens of MT, the overpressure would grow less than in case of a smaller explosion - these have nearly spherical fireballs in nearly uniform air environment.

But when fireball expands past a few km and approaches atmospheric scale height, the upper part of the fireball will be ploughing up less dense air - it will travel faster and expand to lower pressure. And decreasing pressure at the top will release the pressure from the bottom and sides of fireball and slow down their propagation.
 

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