I do not see where simultaneity plays a role. There is only one event of importance at a time and no causality or effect between any two events in my discussion.
As I said, you're obviosly untrained in relativity, so you're unaware of all the pitfalls there are if you define your experiments sloppily.
First thing you have to know is the definition of an event: An event is not simply something happening at a specific time. It is something happening at a specific time
and at a specific position. An event cannot happen at two positions.
So there are three events that are important for the function of the trolley:
As the trolley passes immediately in front of Tom the trolley puts a pair of marks on the fence in front of Tom.
"As the trolley passes immediately in front of Tom" - obiously when the midpoint of the trolley passes a certain position, say the zero position.
"the trolley puts a pair of marks on the fence in front of Tom." - That's two events:
1) the trolley marks a point to the left of Tom.
2) the trolley marks a point to the right of Tom.
These are different events, as they happen at different positions.
Then, there is a statement of simultaneity:
"
As the trolley passes..."
Which implies that all three events are simultaneous. Now there is the question in which frame they are simultaneous. As it is the trolley that does the marking, it seems natural to assume that the events are simultaneous in its frame. If so, your formula and numbers are incorrect and have to be replaced by the one I posted.
Further, there is a cause-effect relation implied that cannot be maintained: If all three events are simultaneous in one frame, they cannot cause each other. So if the midpoint of the trolley states that it is now exactly in front of Tom, how does it trigger the markers instantaneously? They are each half a meter away.
So you have to arrange beforhand that the markers are triggered at the correct time to circumvent the problem.
Ok, this was just your #1.
Do you understand so far what I'm talking about?
Can you derive the formula I gave you for the separation of the marks if they are marked simultaneously in the trolley's frame?
Just ask if you need help at one point or another, these things are notoriously difficult in the beginning.
Ich said:
11) - Why would he expect 0.866 m? The trolley made its marks on moving ground, why shouldn't there be a difference?
Item 2 says specifically that the fence is stationary with Sally and with respect to Tom When Sally stops his motion. The fence does not move.
If "the fence is stationary with Sally and with respect to Tom when Sally stops his motion", it is obviously moving wrt Tom as long as Tom is moving wrt Sally. So Tom sees the trolley mark a moving fence.