Is It Possible to Independently Vary Kij in Both Methods?

nenyan · Mar 21, 2015

I got the result that is consist with references in fisrt case. Is there anything wrong in 2nd way?

Orodruin · Mar 21, 2015

Both are wrong. In the first case you are missing a 2 in both terms (still giving the same equation if you put the variation to zero). In the second case you missed a 2 only on the first term.

nenyan · Mar 21, 2015

Thank you. I see.
K^ij=g^img^jnK_mn
I should consider another K_ij here.

Orodruin · Mar 21, 2015

Yes, you cannot vary K_ij independently of K^ij.

Is It Possible to Independently Vary Kij in Both Methods?

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