Is It Possible to Reach the Speed of Light with a Spacecraft?

Click For Summary
SUMMARY

The discussion centers on the impossibility of a bullet achieving the speed of light when fired from a spaceship traveling at half the speed of light. According to the relativistic addition of velocity formula, the bullet's speed relative to an outside observer would be 0.8c, not c. This conclusion is grounded in Einstein's special theory of relativity, which states that as objects approach the speed of light, their mass increases, requiring infinite energy to reach light speed. Thus, no spacecraft can reach or exceed the speed of light.

PREREQUISITES
  • Understanding of Einstein's special theory of relativity
  • Familiarity with the relativistic addition of velocity formula
  • Basic knowledge of mass-energy equivalence
  • Concept of relativistic mass increase with speed
NEXT STEPS
  • Study the relativistic addition of velocity in detail
  • Explore the implications of mass-energy equivalence in high-speed travel
  • Research the effects of gravity on light speed near black holes
  • Investigate current propulsion technologies and their limitations
USEFUL FOR

Physicists, aerospace engineers, and anyone interested in the fundamental principles of relativity and the limitations of space travel at relativistic speeds.

Andrew Buren
Messages
18
Reaction score
0
If you had a spaceship travleing at half the speed of light then shot a bulit at half the speed of light again, would the bulit appear to go the speed of light relative to an outside obverver?
(All preposed in theory, of cource.)
 
Physics news on Phys.org
If not, why?
 
Andrew Buren said:
If you had a spaceship travleing at half the speed of light then shot a bulit at half the speed of light again, would the bulit appear to go the speed of light relative to an outside obverver?
(All preposed in theory, of cource.)
No. To find the speed of the bullet with respect to that outside observer, you must use the relativistic addition of velocity formula:

V_{a/c} = \frac{V_{a/b} + V_{b/c}}{1 + (V_{a/b} V_{b/c})/c^2}

Which gives: (0.5c + 0.5c)/(1 + (.5)^2) = 0.8 c
 
Last edited:
The "outside observor" being assumed to be one relative to which the spaceship is moving at (1/2)c, of course. There can exist "outside observors" with other speeds relative to the spaceship!
 
Good point. :wink:
 
So this is like the idea that objects within a black hole can appear to be exceeding c, even though they aren't?
 
Hi there,

But no matter what, the bullet would never have c for any observer, in any relative frame.

Cheers
 
NWH said:
So this is like the idea that objects within a black hole can appear to be exceeding c, even though they aren't?

Since we cannot observe an object within a black hole, I have no idea what "appear" can mean here.
 
HallsofIvy said:
Since we cannot observe an object within a black hole, I have no idea what "appear" can mean here.
Hypothetically speaking, of course...
 
  • #10
ccording to Einstein's special theory of relativity, objects gain mass as they accelerate to greater and greater speeds. Now, to get an object to move faster, you need to give it some sort of push. An object that has more mass needs a bigger push than an object with less mass. If an object reached the speed of light, it would have an infinite amount of mass and need an infinite amount of push, or acceleration, to keep it moving. No rocket engine, no matter how powerful, could do tthis
 

Similar threads

  • · Replies 45 ·
2
Replies
45
Views
5K
  • · Replies 51 ·
2
Replies
51
Views
4K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 130 ·
5
Replies
130
Views
15K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 38 ·
2
Replies
38
Views
5K
  • · Replies 53 ·
2
Replies
53
Views
6K
  • · Replies 34 ·
2
Replies
34
Views
3K