Is K*T Equal to hv in Thermal Equilibrium?

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SUMMARY

The equation K*T = hv is valid in the context of thermal equilibrium, where K represents the Boltzmann constant, T is the temperature in Kelvin, h is Planck's constant, and v is the frequency of absorbed light. In the discussed scenario, a sample absorbs light at a frequency of 697 cm-1, allowing the calculation of temperature using the formula T = hv/K. This relationship is grounded in Kirchhoff's Law of thermal radiation, which describes the emission and absorption of radiation by bodies in thermal equilibrium.

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  • Understanding of Boltzmann constant (K)
  • Familiarity with Planck's constant (h)
  • Knowledge of frequency measurement in cm-1
  • Basic principles of thermal equilibrium and Kirchhoff's Law
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Chemist20
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...but, is it true that K*T = hv ? Being K Boltzmann constant...and v the frequency.

Because I have seen this exercise, in which they just say that a sample A in thermal equilibrium (maybe this is the bit that I'm missing out...) absorbs light at 697cm-1, so the temperature of the sample is T = hv/k.

This was done by my teacher, but I don't trust him LOL.

Any ideas please?

Thanks a lot!
 
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