Is K*T Equal to hv in Thermal Equilibrium?

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Chemist20
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...but, is it true that K*T = hv ? Being K Boltzmann constant...and v the frequency.

Because I have seen this exercise, in which they just say that a sample A in thermal equilibrium (maybe this is the bit that I'm missing out...) absorbs light at 697cm-1, so the temperature of the sample is T = hv/k.

This was done by my teacher, but I don't trust him LOL.

Any ideas please?

Thanks a lot!
 

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