Is L(x,y) a Linear Transformation?

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Homework Help Overview

The discussion revolves around determining whether the function L(x,y) = (x+1, y, x+y) qualifies as a linear transformation. The context is linear algebra, specifically focusing on the properties of transformations between vector spaces.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to verify the linearity of the transformation by applying the definition of linear transformations. They express confusion about how to compute L(u+v) and the implications of the transformation mapping from R² to R³.

Discussion Status

Participants are actively engaging with the problem, with some providing clarifications on how to interpret the addition of vectors in R². There is a recognition of differing outcomes when applying the transformation to the sum of vectors versus the sum of their individual transformations.

Contextual Notes

There is an emphasis on understanding the definitions and properties of linear transformations, as well as the specific mapping from R² to R³, which is noted to be a source of confusion for some participants.

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[SOLVED] Linear Transformation

Homework Statement


Determine if this is a linear transformation:

L(x,y) = (x+1, y, x+y)


Homework Equations



This is just one, but I have no clue as to how to even begin. I've been to lecture and read the book over and over again, but i was not given any relevant examples. Could someone please walk me through this? I know that to show it is a linear transformation, i must show that L(u+v) = L(u) + L(v), but i can't seem to find L(u+v)


The Attempt at a Solution



u =
[x
y]

v =
[x'
y']

L(u) + L(v) =
x + x' + 2
y + y'
x + y + x' +y'

I'm not even sure that is correct, but if it is, how does one find L(u+v)? Additionally, the fact that it is a transformation from R^2 => R^3 is throwing me off
 
Last edited:
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The domain is R^2, they mean that (x,y)+(x',y') should be defined by (x+x',y+y'). What's L of that?
 
would L(x+x', y+y') = x+x'+2 ?
y+y'
x+1+y

It's probably extremely obvious, but i still don't understand.
 
L(x+x',y+y') would be (x+x'+1,y+y',x+x'+y+y'). Look at the definition. Substitute x+x' -> x and y+y' ->y. Notice that's different from what you found for L(u)+L(v).
 
ah that makes sense! I think i understand now.Thx for the help!
 

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