Is my Cockcroft-Walton accelerator design correct?

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SUMMARY

The forum discussion revolves around the design and functionality of a Cockcroft-Walton accelerator, specifically for a science fair project. The design includes a polished steel terminal, a hydrogen discharge tube as the proton source, and a six-stage Cockcroft-Walton voltage multiplier estimated to output around 72 kV. Key concerns raised include the adequacy of the design for achieving a usable proton beam, the importance of vacuum conditions in the beam tube, and the necessity of optimizing the ion source for better performance. Participants emphasize the need for safety measures and suggest further calculations regarding the Coulomb barrier to enhance the design.

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eigenmax
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I am building a Cockcroft-Walton accelerator for a science fair project, so how does this design sound?

Starting from the top, there is a polished steel terminal, like a VDG terminal. Inside here is the proton source and power supply to the source (the source is a hydrogen discharge tube) . The top terminal is connected to the output (positive), of a Cockcroft-Walton voltage multiplier. From the top terminal comes the accelerator tube. It is a glass (probably borosilicate) pipe.

Three polished copper drift tubes are fitted within it. The highest tube is connected to the spherical terminal at the top. The middle tube is connected to the middle of a six-stage CW voltage multiplier. This is half the top terminal voltage (still positive). The bottom tube is connected to the start of the multiplier , ground. The proton beam enters a machined aluminium chamber and strikes a target. This creates gamma rays which can be detected. If lithium is struck with the beam, alpha particles are created which escape through a mica window in the target chamber and are detected by a end-window Geiger counter.

Should I place external corona needles connected to the drift tubes, outside the accelerator tube, to equalise potential over the tube, or is my current design fine? Should a seal the proton source with a mica window or us the design from http://info.ifpan.edu.pl/firststep/aw-works/fsII/alt/altineller.pdf. If I don't seal the source, won't the hydrogen just escape down the acceleration tube?

Please improve upon it and tell me what I'm doing wrong.
Thanks so much,
Max
 
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Just for starters. Do you have sketches/drawing of your device? What is your goal or purpose for this device? What is you design terminal voltage? What radiation safety procedure do you intend to implement? An needless to say I presume you are well aware of the HV safety issues both for users and spectators.
 
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gleem said:
Just for starters. Do you have sketches/drawing of your device? What is your goal or purpose for this device? What is you design terminal voltage? What radiation safety procedure do you intend to implement? An needless to say I presume you are well aware of the HV safety issues both for users and spectators.
Yes, I do have the sketches and drawings.
My goal is to create a proton beam for the bombardment of targets.
The terminal is charged from a Cockcroft-Walton multiplier, if that's what you mean.
The target chamber is shielded with lead, except for the window. I will also make use of dosimeters.
And yes, I'm aware of HV safety.
Thanks for replying, so do you think it will work?
 
eigenmax said:
The terminal is charged from a Cockcroft-Walton multiplier, if that's what you mean.
He is asking what the output voltage of your multiplier is...
 
berkeman said:
He is asking what the output voltage of your multiplier is...
Oh, sorry. I don't know exactly but it's probably about 72Kv. I got that from a rough estimate, I haven't got a high-voltage multimeter probe yet, so can't measure exactly.
 
eigenmax said:
Thanks for replying, so do you think it will work?

Going on just your description it is difficult to say how successful you will be in obtaining a usable beam.
Getting a usable beam may be more difficult than you expect. How do you expect to evaluate its performance? Beam current for example and are you measuring what you think you are

At 72 KV I wouldn't hold my breath on seeing any nuclear reaction products. the coulomb barrier will be too high most of your beam to penetrate to a distance which will result in a reaction.

I should add that you might want to check for soft x-ray too say from back streaming electrons flying up toward the HV terminal.
 
Thanks for the help! What is the value of the Coulomb barrier, so I can design a higher voltage multiplier? What could I do to create a usable beam?
Thanks,
 
eigenmax said:
What is the value of the Coulomb barrier, so I can design a higher voltage multiplier

You should be able to compute a reasonable approximation by determining from Coulomb's law and assume that the target nucleus' surface and projectile surface just touch. the work (energy required) you must do to bring them that close.

As far as useable beams are concerned there may be a lot of trial and error. But factors that are important are purity of the gas you use , the method you use to extract the ions from the source and how you focus the beam coming out of the source and down the beam tube. you don't want the beam hitting anything after it extracted. Also the beam tube vacuum is important the longer the tube the lower the vacuum should be.
 
Ok thanks, and very finally, the acceleration method is correct though, with the beam accelerated down lower potentials to ground ?
Thanks,
Max
 
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eigenmax said:
Ok thanks, and very finally, the acceleration method is correct though, with the beam accelerated down lower potentials to ground ?

Yes, An one additional point. In trying to experimenting with and optimizing the ion source you might construct a setup specifically designed for this instead of putting it on the CW machine and measuring current at the end of the beam tube.
 
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gleem said:
Yes, An one additional point. In trying to experimenting with and optimizing the ion source you might construct a setup specifically designed for this instead of putting it on the CW machine and measuring current at the end of the beam tube.
Ok, thanks a lot !
 

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