Is my proof that the Euler phi function is multiplicative correct?

  • Level: Graduate 
  • Thread starter Thread starter icystrike
  • Start date Start date
  • Tags Tags
    Proof
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
6 replies · 4K views · last reply
icystrike
Messages
444
Reaction score
1
I'm trying to write a sound prove to proof that phi-function is multiplicative in the aspect of number theoretic function. Please comment on my proof. Thanks in advance.

Handwritten-style typeset proof that the Euler phi function is multiplicative: a lemma that gcd(a,mn)=1 iff gcd(a,m)=1 and gcd(a,n)=1, then nested sums over coprime a leading to phi(mn) = phi(m)phi(n).
 
Attachments
  • Handwritten-style typeset proof that the Euler phi function is multiplicative, with a lemma gcd(a,mn)=1 iff gcd(a,n)=1 and gcd(a,m)=1, followed by a chain of sums over coprime a leading to phi(m)phi(n).
    mul.jpg
    17.1 KB · Views: 997
Physics news on Phys.org
Hi, one question,

how did you step from "the sum where gcd...m and gcd...n" to "(the sum where gcd...m) times (the sum where gcd...n)" ?
 
The passage from the first line to the second is not correct; the set of a's such that gcd(a,m) = 1 may not be disjoint from the gcd(a,n) = 1.

One suggestion: instead of working with the sums, try using Euler's formula for [tex]\varphi[/tex]:

[tex]\varphi\left(n\right) = n\left(\ 1 - \frac{1}{p_{1}}\right)\left(\ 1 - \frac{1}{p_{2}}\right)...\left(\ 1 - \frac{1}{p_{k}}\right)[/tex]

Where [tex]p_{1},...,p_{n}[/tex] are the prime factors of n.
 
Printed proof of a lemma: for integers a, b, c, gcd(a, bc) = 1 if and only if gcd(a, b) = 1 and gcd(a, c) = 1, with the proof written in running text.



Thus, the lemma is answered , so will my proof for multiplicative function to be true?
 
Attachments
  • Printed page showing a Lemma stating that for integers a, b, c, gcd(a, bc) = 1 if and only if gcd(a, b) = 1 and gcd(a, c) = 1, followed by its proof in two paragraphs.
    lemma.JPG
    63.8 KB · Views: 623
Nobody questioned the validity of gcd(a,mn) = 1 iff gcd(a,m) = gcd(a,n) = 1; this is true. It's simply the way you split the sums that's a bit unclear, and could be improved.