Is non continuous function also not Bounded ?

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SUMMARY

A non-continuous function can indeed be bounded, as demonstrated by specific examples in the discussion. The functions f(x) = x for 0 ≤ x ≤ 1 and f(x) = x + 1 for 1 ≤ x ≤ 2, along with g(x) = 0 for rational x and g(x) = 1 for irrational x, illustrate that discontinuity does not imply unboundedness. The logical structure of implications is clarified, emphasizing that the negation of a conditional statement does not lead to a definitive conclusion about the boundedness of non-continuous functions.

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Lancelot1
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Dear all,

I am trying to figure out if a non continuous function is also not bounded. I know that a continuous function in an interval, closed interval, is also bounded. Is a non continuous function in a closed interval not bounded ? I think not, it makes no sense. How do you prove it ?

Thank you !
 
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You are making an error in logic. The opposite of "if A then B" is NOT "if not A then not B". It is "if not A then we don't know anything about B"!

For example the functions f(x)= x for [math]0\le x\le 1[/math], f(x)= x+ 1 for [math]1\le x\le 2[/math] and g(x)= 0 if x is rational, g(x)= 1 if x is irrational are discontinuous (g badly discontinuous) but are bounded functions.
 

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