Is r=L Always Valid for Centripital Force and Velocity in Circular Motion?

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SUMMARY

The discussion confirms that in circular motion, the centripetal force equation can be applied using the distance from the center of mass (CM) to the point of suspension as the radius (r = L). This conclusion is supported by analyzing a uniform rod's tension when spun, demonstrating that the centripetal acceleration (a = ω²L) holds true for various bodies. The participants agree that this principle is a standard result in physics, validating the use of L in the centripetal force equation.

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  • Understanding of centripetal force and acceleration concepts
  • Familiarity with rotational dynamics and angular velocity (ω)
  • Knowledge of center of mass (CM) calculations
  • Basic integration techniques for continuous mass distributions
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Abhishekdas
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Circular motion...

Homework Statement


If a wire has some length and a any random abject is attached to it and we whirl it around in a cirle...this object has finite(non negligible dimentions)...Lets say we know the distance of the point of suspension from the centre of mass of this body(let it be L)...
Now for centripetal force mw2r can we take this r=L? If so why? and can we then say v(vel of CM)=Lw?


Homework Equations





The Attempt at a Solution

 
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Why don't you try a simple example and see what happens? Say you have a short, thin, uniform but heavy rod of mass M and length a. Determine the linear mass density. Now, suppose your wire is attached to one end of this rod and it's set spinning as you suggest. Calculate the tension in the wire for a given rotational velocity (it'll require an integration over the length of the rod). See if it matches the value you get of you assume all the mass is at the center of mass of the rod.
 


Hi...
it comes out to be true in this case...But is it a proven thing in physics?...

We know that net force acting in a body = ma here a = acc of CM...this is a property of CM...stnadard result...
now here Tension = m*acceleration of CM...her acc of CM is mw^2*L...

So it should be true for all bodies in general...So is this a valid proof(using the standard result) for the fact that in mw^2*r we can always take the r as the dist of point of suspension from the centre of mass? Does that answer my question...

I mean it is sudddenly getting clear to me and i am pretty sure its always true(i didnt think of the standard result in that way...)...
 

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