Is T: M22 --> R a Linear Transformation?

  • Thread starter Thread starter FourierX
  • Start date Start date
  • Tags Tags
    Linear
Click For Summary

Homework Help Overview

The discussion revolves around determining whether the function T, defined from the space of 2x2 matrices (M22) to the real numbers (R), qualifies as a linear transformation. The function is expressed as T [a b; c d] = a + b + c + d.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the properties of linear transformations, specifically checking the conditions T(u + v) = T(u) + T(v) and T(ru) = rT(u). They discuss the implications of these properties using specific matrices and arbitrary scalars.

Discussion Status

Some participants have confirmed that the first condition appears to be satisfied, while others are verifying the second condition. There is an ongoing exploration of whether both conditions hold true for the function T.

Contextual Notes

Participants are working under the assumption that the definitions of linear transformations are correctly applied, and they are using specific matrices to test these properties. The discussion reflects a collaborative effort to clarify the requirements for T to be a linear transformation.

FourierX
Messages
73
Reaction score
0
Linear Transormation?

Homework Statement



Is function T a linear transformation for T: M22 --> R by

T [a b]
[c d] ( i.e. T [a b ; c d] )= a + b + c + d

Homework Equations

T ( u + v) = T(u) + T(v)

T(ru) = rT(u)

The Attempt at a Solution



The matrix form is confusing me
 
Physics news on Phys.org


Let U be the matrix you defined and let r be an arbitrary scalar. You know how to calculate rU and you have the formula for calculating T(U), so does T(rU) = rT(U)?

For the next part, define another matrix similarily as you did except with different letters. Call it V. Does T(U + V) = T(U) + T(V)?
 


the first part T(rU) = rT(U) satisfies
 


and i so does the second part! Am I right?
 


If you can show it then you are done.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
4
Views
2K
Replies
0
Views
1K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 18 ·
Replies
18
Views
3K