Is the Area of y=1/cos^2x Divergent?

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Homework Statement


Find the area of [tex]y= \frac{1}{\cos^2 x}[/tex] from [tex]x=0[/tex] to [tex]x = \frac{\pi}{2}[/tex].

2. The attempt at a solution


[tex]\int \frac{1}{\cos^2 x}[/tex] from 0 to [tex]\frac{\pi}{2}[/tex].
equals [tex]\tan x[/tex]
and take the limit from the negative side of [tex]\frac{\pi}{2}[/tex].
since limit of tan at [tex]\frac{\pi}{2}[/tex] is [tex]\infty[/tex]
the funtion is divergent.
so the area doesn't exist.
 
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