Is the Area of y=1/cos^2x Divergent?

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Homework Help Overview

The problem involves finding the area under the curve defined by the function y = 1/cos²(x) from x = 0 to x = π/2, focusing on the behavior of the integral and its convergence.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the evaluation of the integral of 1/cos²(x) and its implications regarding divergence. There is an attempt to analyze the limit of the function as x approaches π/2.

Discussion Status

Some participants assert that the integral is divergent, while others confirm this perspective. The discussion reflects a consensus on the divergence of the area under the curve, although the reasoning is not fully explored by all participants.

Contextual Notes

There is an indication that the original poster is seeking validation of their reasoning regarding the divergence of the integral, and some participants express a desire for further engagement in the discussion.

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Homework Statement


Find the area of [tex]y= \frac{1}{\cos^2 x}[/tex] from [tex]x=0[/tex] to [tex]x = \frac{\pi}{2}[/tex].

2. The attempt at a solution


[tex]\int \frac{1}{\cos^2 x}[/tex] from 0 to [tex]\frac{\pi}{2}[/tex].
equals [tex]\tan x[/tex]
and take the limit from the negative side of [tex]\frac{\pi}{2}[/tex].
since limit of tan at [tex]\frac{\pi}{2}[/tex] is [tex]\infty[/tex]
the funtion is divergent.
so the area doesn't exist.
 
Last edited:
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I was wondering why no one answer this forum, you only have to check if I am right( yes or no).
 
The integral is divergent.
 
Yes, you are right.
 

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