Is the Average Value of Cos^2 Indeed 1?

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The average value of cos^2 over the interval from 0 to 2π is not 1, but rather 1/2, as derived from the integral definition of average value. This is supported by the identity cos^2 + sin^2 = 1, which indicates that both terms have equal averages. The discussion references a common teaching point from a physics class, emphasizing that the average value of the cosine squared function over a closed path is consistently stated as 1/2. Therefore, the assertion that the average value of cos^2 is 1 is incorrect. Understanding this concept is essential for accurate mathematical and physical analysis.
71GA
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Hello!
I want to know if average value of cos^2 is indeed 1 ?

Thank you.
 
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Use the integral definition of average value and integrate from 0 to 2 PI. See what you get.
 
cos2 + sin2 = 1, so its average = 1, and each term has the same average, so the average value of cos2 is 1/2.
 
I will never forget sitting in sophomore physics class in college and the Professor always said "the average value of the cosine squared function over a closed path is 1/2."
 
thank you
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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