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If a space is of n dimension, then the boundary of this space is n-1 dimension or not?
The discussion revolves around the dimensionality of boundaries in n-dimensional spaces, questioning whether the boundary of an n-dimensional space is always n-1 dimensional. The scope includes theoretical considerations and conceptual clarifications regarding boundaries in various dimensional contexts.
Participants express multiple competing views on the nature of boundaries in n-dimensional spaces, with no consensus reached regarding the validity or applicability of the boundary concept across different contexts.
Limitations in the discussion include the vagueness of the term "boundary," the dependence on specific definitions, and the presence of pathologies in certain mathematical spaces that complicate the understanding of boundaries.
Say it more clearly, why we use a line or curve to divide the 2 dimension manifold, why we use a 2 dimension surface to divide the 3 dimension manifold?Hurkyl said:Alas, his question was incredibly vague; as stated it doesn't make any sense, because the concept of "boundary" doesn't really make sense for an abstract space, and there are lots of pathologies even for "usual" spaces.
For example, consider the graph of the function
y = \sin \left( \frac{1}{x} \right) \quad \quad x \in (0, 1).
How are you going to define the boundary of this curve? Once you've chosen a definition, is it zero-dimensional? (Note that the closure of the graph of this curve consists of the entire line segment x = 0 \wedge y \in [-1, 1])