Is the concept of binding energy in nuclear reactions contradictory?

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Discussion Overview

The discussion revolves around the concept of binding energy in nuclear reactions, particularly addressing the apparent contradiction between the release of energy during reactions and the increase in binding energy of the resulting nucleus. Participants explore the implications of binding energy, mass defect, and stability of nuclei.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions how energy can be released in a nuclear reaction while the binding energy of the resulting nucleus increases, suggesting a potential contradiction.
  • Another participant states that binding energy is always negative, indicating that more binding energy means a more negative value, which requires energy to separate nucleons.
  • A participant seeks clarification on the concept of negative binding energy and its implications, while also asking for feedback on their previous explanations.
  • One participant provides an analogy involving a boulder to illustrate the concept of stability and energy release, suggesting that a more stable state requires more energy to disassemble.
  • Another participant confirms their understanding of the topic after receiving responses from others.
  • A question is raised regarding the units of binding energy, specifically whether it is measured in Joules/Mole.
  • A later reply clarifies that while binding energy can be expressed in Joules/Mole, MeV/atom or MeV/nucleon are more conventional in nuclear physics.

Areas of Agreement / Disagreement

Participants express differing views on the interpretation of binding energy and its implications in nuclear reactions. Some agree on the definitions and implications of binding energy, while others seek further clarification and express uncertainty about the concepts discussed.

Contextual Notes

The discussion includes various interpretations of binding energy and its relationship to energy release in nuclear reactions. There are unresolved aspects regarding the definitions and implications of binding energy, particularly in relation to stability and energy requirements for nuclear processes.

Who May Find This Useful

This discussion may be useful for individuals interested in nuclear physics, particularly those exploring the concepts of binding energy, nuclear stability, and energy transformations in nuclear reactions.

eroxore
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Hello forum.

So the other day I was pondering properties of atomic nucleus, in particular the property of binding energy (mass defect). Whenever a nucleus -- through a nuclear reaction of some sort -- is split or joined into a more stable nucleus, energy is released. However the newly formed nucleus which is more stable has more binding energy than the nucleus from which it formed. How can we then say that energy is released? Is it not rather contradictory? The binding energy grew post-reaction, but should it not have decreased since energy was released?

(Maybe I am just interpreting binding energy incorrectly, since it essentially just measures the change in mass in nucleons in a free versus bounded state and therefore does not necessarily have anything to do with the pre-reaction nucleus).

If we look at masses-per-nucleon, this problem can be intuitively explained: The newly formed and more stable nucleus has less mass-per-nucleon than the nucleus from which it formed. According to E = mc^2, that means that the new nucleus cumulatively has less energy than the pre-reaction nucleus in terms of the masses of the elementary particles. Thus one realizes the nucleons lost energy during the reaction and one can reasonably conclude that lost energy was the energy released in the reaction.

Another perspective on the same problem is that "less stable" can be interpreted as "more/highly energized". So if a nucleus joins/splits into a more stable one, we can conclude that this "excess" (if you will) energy prior to the reaction has been released throughout the reaction. So this is why for example iron will not spontaneously join/split into any other nucleus. It is because iron is as stable is at gets (for all intents and purposes) and in order for iron to form a less-stable nucleus (i.e. more energized nucleus), energy must be inserted externally into the system.

Much appreciated if anyone could help me understand how the increasing of binding energy despite releasing energy throughout the reaction is true.
 
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Binding energy is always negative (you need energy to split the atoms into protons and neutrons), and "more binding energy" / "larger binding energy" ... always means "more negative" (more energy is needed to separate them).

Edit: Clarified
 
Last edited:
mfb said:
Binding energy is always negative, and "more binding energy" / "larger binding energy" ... always means "more negative".

What, really? I have never heard of that, care to elaborate? Also, what are your thoughts on the other two explanations I presented?
 
eroxore said:
What, really? I have never heard of that, care to elaborate? Also, what are your thoughts on the other two explanations I presented?

Per wiki:

Binding energy is the mechanical energy required to disassemble a whole into separate parts. A bound system typically has a lower potential energy than the sum of its constituent parts — this is what keeps the system together. Often this means that energy is released upon the creation of a bound state. This definition corresponds to a positive binding energy. (This definition also often causes confusion. For example: A prominent term in chemistry is the 'free energy of binding', which is the difference between the bound and unbound states and thus negative).

And your explanations are more or less correct. A higher binding energy per nucleon means that it takes MORE energy per nucleon to disassemble the nucleus.
 
Suppose you have a boulder sitting on top of a cliff. If you give the boulder a little nudge, it will fall off the cliff. When it hits the ground, it releases energy (heat, sound, etc). It is now more stable, because giving it a nudge can't cause it to fall any further, it's at the bottom and has nowhere else to go. The boulder at the bottom of the cliff is also now more tightly bound to the earth. If you wanted to launch the boulder out of Earth's gravitational influence, it would take more energy to do so starting from the bottom of the cliff than the top.
 
Excellent responses, I believe I have finally grasped it intuitively. Thanks!
 
Question: Is binding energy measured in Joules/Mole? I'm having wikipedia issues...
 
It is possible to express binding energy in Joule/Mole, but that is a very unconventional unit for nuclear physics. MeV/atom or MeV/nucleon are more common.
 

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