Is the covalent character of sodium chloride affected by its polarity?

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The discussion centers on the covalent character of sodium chloride (NaCl) and its dipole moment, which is measured at 9 debye with a sodium-chlorine distance of 0.28 nm in the crystalline state. The initial calculation of 2/3 of an electron was corrected by using the gas phase value of 0.236 nm, resulting in approximately 0.79 e. Participants emphasized that no bond is 100% ionic, including NaCl, due to the polarizing effect of the sodium ion on the chloride ion and the inherent covalent character present in all ionic compounds.

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I found out that sodium chloride has a dipole moment of 9 debye, and a sodium-chlorine distance of .28 nm. When I divide one by the other, I get 2/3 of an electron.

Did my math go wrong somewhere, or is this supposed to happen? I expected something close to a full elementary charge.
 
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Well, because it's an ionic bond.
 
Doesn't mean the electron can't spend a fraction of its time in the neighbourhood of the Na+ ion ?

Link claims the 0.28 nm is in the crystalline state and somewhat greater than in the gaseous state.
 
I know that, but Ithought it would be at least 90% ionic, given that this is THE classic ionic compound. I mosly wanted to know if my math is right.

So the electron really spends that much time in the sodium?
 
Link tells the story: closer than 0.236 nm and the core electrons start pushing back
 
You also have to take into account that the sodium ion polarizes the chloride ion. This will reduce the dipole moment considerably.
 
Tiiba said:
I found out that sodium chloride has a dipole moment of 9 debye, and a sodium-chlorine distance of .28 nm. When I divide one by the other, I get 2/3 of an electron.

Did my math go wrong somewhere, or is this supposed to happen? I expected something close to a full elementary charge.

There are two problems in your analysis.

1- First you used the solid state NaCl separation in your calculation. Instead you should use the gas phase value , 0.236 nm. If you do this you get ~ 0.79 e. In the solid state, the net dipole moment of NaCl crystal is zero due to the centrosymmetry of the structure. This is , of course, not the case for the gas phase molecule.

2- Even the value of 0.79 e is not a good metric for the ionicity of NaCl molecule because it is calculated assuming that both Na and Cl are point charges. While this point charge approximation is reasonable for the Na ion, it is not for the Cl ion. The latter is sort of a "fluffy" ion which makes it difficult to represent it as a point charge.
 
  • #10
Borek said:
No bond is 100% ionic.
Wouldn't a bond of the most electronegative and least electronegative atoms (so Fluorine and Francium) be 100% ionic, based on the 0-3.3 scale of electronegativity difference?
 
  • #11
Why should it?

Sure, it is a best candidate we can think of, but there is no reason to think this particular one will be different from all others we know (of which none is 100% ionic).
 
  • #12
Borek said:
Why should it?

Sure, it is a best candidate we can think of, but there is no reason to think this particular one will be different from all others we know (of which none is 100% ionic).
By saying "all others we know", do you mean all other ionic compounds in general? If so, are you saying that there would be no difference between a 60% ionic compound, and say, an 80% ionic compound?
 
  • #13
Comeback City said:
By saying "all others we know", do you mean all other ionic compounds in general? If so, are you saying that there would be no difference between a 60% ionic compound, and say, an 80% ionic compound?
Probably both dissociate into hydrated ions in water. Seriously, where does this difference matter?
 
  • #14
Comeback City said:
By saying "all others we know", do you mean all other ionic compounds in general?

Yes.

If so, are you saying that there would be no difference between a 60% ionic compound, and say, an 80% ionic compound?

No. What I am saying is that they all contain some covalent character. The degree to which they are covalent changes, but there are no reasons to assume it will disappear at some particular value of electronegativity difference.
 
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  • #15
Borek said:
Yes.
No. What I am saying is that they all contain some covalent character. The degree to which they are covalent changes, but there are no reasons to assume it will disappear at some particular value of electronegativity difference.
That way of thinking makes more sense. Thanks.
 

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