Is the Differentiation of Power in a Circuit Correct?

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SUMMARY

The power of an electrical circuit is defined by the formula P = (E^2 * R) / (R + r)^2, where E represents the electromotive force (emf) of the battery. To find the maximum power, the differentiation of power with respect to resistance R is necessary. The correct derivative, obtained using the quotient rule, is ((R + r)E^2 - 2RE^2) / (R + r)^3. This derivative equals zero when the numerator is zero, leading to the conclusion that maximum power occurs when r equals R.

PREREQUISITES
  • Understanding of electrical circuit theory
  • Familiarity with differentiation and calculus
  • Knowledge of the quotient rule in calculus
  • Basic concepts of electromotive force (emf)
NEXT STEPS
  • Study the application of the quotient rule in calculus
  • Explore the concept of maximum power transfer theorem in electrical circuits
  • Learn about the relationship between resistance and power in circuits
  • Investigate the implications of varying resistance in practical circuit design
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Electrical engineers, physics students, and anyone interested in optimizing power in electrical circuits will benefit from this discussion.

Joza
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Power of an electrical circuit is equal to current squared times resistance.

My expression for current is: E/(R + r), where E is emf of battery.

So, my expression for Power, P, is:

P=((E^2)R)/(R + r)^2

I would like to differentiate P with respect to R, to find where the slope is zero, ie., the maximum power.
I am having some trouble though. I used the quotient rule and got:

((R + r)E^2 - 2RE^2)/(R + r)^3

Is this correct? I need to know where this is zero, but I am a bit unsure about where to go from here.
 
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Yes, that is correct. But I think you will make the problem much easier by combining those "R2"s!
[tex]\frac{(R+r)E^2- 2RE^2}{(R+r)^3}= E^2\frac{r- R}{(R+r)^3}[/itex]<br /> and, of course, a fraction is only 0 where the numerator is 0.[/tex]
 
Ah, excellent!

I guess I was a bit too tired to realize I should expand it.

And of course it's zero then...:-p why didn't I see that!

That agrees perfectly, because it's 0 when r=R. And that is what I was looking for!

Brilliant mate, cheers!:biggrin:
 

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