MHB Is the Double Factorial Series Convergent with Stirling's Asymptotic Formula?

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The discussion centers on proving the convergence of the series $ \sum_{s}^{} \frac{(2s-1)!}{(2s)!(2s+1)}$ using Stirling's asymptotic formula. Participants explore the relationship between double factorials and regular factorials, noting that Stirling's formula can simplify calculations. A less common Stirling formula for double factorials is suggested as potentially helpful. The original poster struggles with various convergence tests, including the ratio test and L'Hospital's rule, but finds no conclusive results. Ultimately, they receive guidance on converting double factorials to regular factorials, which aids in their understanding.
ognik
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Hi, question is - show that the following series is convergent: $ \sum_{s}^{} \frac{(2s-1)!}{(2s)!(2s+1)}$

Hint: Stirlings asymptotic formula - which I find is : $n! = \sqrt{2 \pi n} \left( \frac{n}{e} \right)^n $

I can see how this formula would simplify - but can't see how it relates to the double factorial !
 
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Um, not sure why no replies, always feel free to tell me bluntly if I must do something else or different...

I know of course that (2s-1)! = (2s-1)(2s-3)(2s-5) ...3.1 but cannot see how Stirling's formula helps or even relates...

Liebnitz' criteria requires L'Hospital and I don't know how to differentiate a dbl factorial. Tried with Wolfram and it returns a complex series that isn't going to help. I also don't know how to integrate a dbl factorial, so the integral test won't help.

I tried the ratio test (the dbl factorials simplified nicely) but got L=1, i.e. inconclusive.

I tried expanding a few terms, got -7/8, 11/16, -225/64, 133/256 ... and don't see a partial sum formula emerging from that.

Any suggestions?
 
Hint:

Convert the double factorial to a regular factorial.
 
ognik said:
Hi, question is - show that the following series is convergent: $ \sum_{s}^{} \frac{(2s-1)!}{(2s)!(2s+1)}$

Hint: Stirlings asymptotic formula - which I find is : $n! = \sqrt{2 \pi n} \left( \frac{n}{e} \right)^n $

I can see how this formula would simplify - but can't see how it relates to the double factorial !
As well as the Stirling approximation formula for $n!$, there is a less well known Stirling formula for the double factorial, namely $$n! \approx \Bigl(\frac2\pi\Bigr)^{\frac14(1-\cos(n\pi))}\sqrt\pi n^{(n+1)/2}e^{-n/2}$$ (see Double factorial: Introduction to the factorials and binomials). That might perhaps be helpful here.
 
If the hint didn't help you might want to see Example 4.5 in https://zaidalyafeai.files.wordpress.com/2015/09/advanced-integration-techniques.pdf. There I do a conversion between double factorial and a regular factorial.
 
ognik said:
Hi folks, thanks for all help. Once I had that suggestion, I found some useful identities here - Double Factorial -- from Wolfram MathWorld - that sorted me out.

Please post your solution if you have time. This will help future thread readers.
 

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