Is the Function f=tan(2x)/x Continuous at x=0?

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SUMMARY

The function \( f(x) = \frac{\tan(2x)}{x} \) can be defined at \( x=0 \) to ensure continuity. The limit as \( x \) approaches 0 is calculated as \( \lim_{x\to 0} \frac{\tan(2x)}{x} = 2 \). By defining \( f(0) = 2 \), the function becomes continuous everywhere, satisfying the condition \( \lim_{x\to 0} f(x) = f(0) = 2 \).

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cbarker1
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Let $f=tan(2x)/x$, x is not equal to 0.

Can the f be defined at x=0 such that it is continuous? I answered yes. I am wondering if the answer is correct. Thank you for your help

CBarker1
 
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Compute limit at $0$. What do you get?
 
I got 2.
 
Cbarker1 said:
I got 2.

So,
$$\lim_{x\to 0} \frac{\tan 2x}{x} = 2$$
Now define the function,
$$ f(x) = \left\{ \begin{array}{ccc}(\tan x)/x & \text{if} & x\not = 0 \\ 2 & \text{if}& x=0 \end{array} \right. $$

This function is continuous everywhere because at $0$ we have $\lim_{x\to 0}f(x) = f(0) = 2$.
 

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