Is the function p(x) = sinx invertible?

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Homework Help Overview

The discussion revolves around the function p(x) = sin(x) and its invertibility. Participants are exploring the characteristics of the sine function, particularly in relation to its one-to-one nature and the implications for invertibility.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are examining the function's behavior at specific values, questioning whether it is one-to-one based on outputs for different inputs. There is a focus on understanding the definitions of one-to-one and many-to-one functions.

Discussion Status

The discussion is active, with participants providing insights and prompting further exploration of definitions and characteristics of the sine function. Some guidance has been offered regarding the need to consider all pairs of inputs when determining one-to-one properties.

Contextual Notes

There is mention of using degrees versus radians in the context of trigonometric functions, which may affect understanding. Participants are also encouraged to refer to graphical representations for better insight.

synkk
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take the function p(x) = sinx

i'm asked to describe the function but I'm not sure what to say as if we take p(90) then we get the value of 1, and if we take p(-90) we get -1, so this would suggest a one-on-one function, but if we take p(360) and p(-360) then the value will be 0 which suggests a many-to-one function,

So which is it?
 
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List the different descriptions/labels available to you and their definitions and you will see.
 
(In math, we usually express the arguments for trig functions as radians instead of degrees. There's technically nothing wrong with degrees, but you should just know that's how it's usually done. More importantly, if you do use degrees, you need to include the symbol for degrees: sin(90) means the sine of 90 radians, not 90 degrees.)

Look at the plot for sin(x): http://www.wolframalpha.com/input/?i=sin(x) and try to answer to question based on that.

If f(x) = f(y) for even one pair of non-equal numbers x and y then the function cannot be one-to-one. You showed in your question that there is at least one such pair. Just saying that for a single number, f(x) = f(-x) (like you did for 90 degrees) is never enough to conclude that a function is one-to-one, it has to be true for every pair of numbers x,y that f(x) doesn't equal f(y).
 
thanks
 
I think you need to determine whether the function is one-one, onto, odd, even, etc.
Hence the function is invertible or not...
 

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