Is the Hermitian Conjugate of an Operator Always Hermitian?

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SUMMARY

The discussion centers on the Hermitian conjugate of the operator \( a = x + \frac{d}{dx} \) and whether it is Hermitian. The operator \( x \) is confirmed to be real, leading to the conclusion that \( x^* = x \). Key considerations include the domain of \( a \) as an operator in \( L^{2}(\mathbb{R},dx) \) and the implications for the adjoint's existence and symmetry. The analysis reveals that the operator's adjoint must be examined within the constraints of its domain to determine its Hermitian nature.

PREREQUISITES
  • Understanding of Hermitian operators in quantum mechanics
  • Familiarity with the position operator and its properties
  • Knowledge of functional analysis, particularly in Hilbert spaces
  • Basic calculus, specifically differentiation and integration
NEXT STEPS
  • Research the properties of Hermitian operators in quantum mechanics
  • Learn about the domain of operators in \( L^{2}(\mathbb{R},dx) \)
  • Study the concept of adjoint operators and their significance
  • Explore examples of symmetric operators and their applications
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Students and professionals in quantum mechanics, physicists studying operator theory, and mathematicians focusing on functional analysis will benefit from this discussion.

danny271828
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Homework Statement



a = x + \frac{d}{dx}

Construct the Hermitian conjugate of a. Is a Hermitian?

2. The attempt at a solution

<\phi|(x+\frac{d}{dx})\Psi>

\int\phi^{*}(x\Psi)dx + <-\frac{d}{dx}\phi|\Psi>

I figured out the second term already but need help with first term... am I on the right track?
 
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Well, x is real. It's the position operator. So x^*=x.
 
HINTS:

1.What's the domain of "a" as an operator in the L^{2}(\mathbb{R},dx) ?
2. Stick to that domain. Consider the matrix element of that operator among 2 vectors in that Hilbert space. What restrictions do you get when trying to find the adjoint ? Therefore ?
3. Does the adjoint exist ?
4. What's its domain ?
5. Is the "a" operator hermitean/symmetric ?
 

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