Is the Integral of an Analytic Function on a Closed Contour Purely Imaginary?

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SUMMARY

The integral of an analytic function $f$ on a simple closed contour $c$ in the complex plane is proven to be purely imaginary through the evaluation of the integral $\displaystyle\int_c \overline{f(z)}f’(z)\, dz$. This result is established by utilizing properties of analytic functions and their conjugates, confirming that the integral does not yield a real component. The discussion emphasizes the significance of analytic functions in complex analysis.

PREREQUISITES
  • Understanding of analytic functions in complex analysis
  • Familiarity with complex integration techniques
  • Knowledge of contour integration and closed contours
  • Basic concepts of complex conjugates
NEXT STEPS
  • Study the properties of analytic functions in detail
  • Learn about Cauchy's integral theorem and its applications
  • Explore the implications of the Cauchy-Riemann equations
  • Investigate the relationship between analytic functions and their conjugates
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Mathematicians, students of complex analysis, and anyone interested in the properties of analytic functions and their integrals.

Euge
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Here is this week's POTW:

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Suppose $f$ is analytic on a simple closed contour $c$ in the complex plane. Prove $\displaystyle\int_c \overline{f(z)}f’(z)\, dz$ is purely imaginary.-----

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No one answered this week’s problem. You can read my solution below.
The real part of the integral is
$$\frac{1}{2} \int_c \overline{f(z)}f’(z)\, dz + f(z)\overline{f’(z)}\, d\overline{z} = \frac{1}{2}\int_c \overline{f(z)}df(z) + f(z)d\overline{f(z)} = \frac{1}{2}\int_c d\lvert f\rvert^2 = 0$$
 

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