Is the Limit Infinity or Does It Not Exist at a Vertical Asymptote?

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The discussion focuses on the nature of limits at vertical asymptotes, specifically addressing the function f(x) = 1/x². As x approaches 0, the limit of f(x) approaches infinity from both sides, leading to the question of whether the limit is considered infinity or if it does not exist. The consensus is that while the limit approaches infinity, it is technically correct to state that the limit does not exist since infinity is not a real number.

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Jimmy25
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This has been bugging for a while and I haven't found an answer.

Say you have a function with a vertical asymptote. This asymptote approaches infinity from both sides.

The limit approaching from either side would be infinity. So would you say the limit is infinity or does not exist?
 
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Here's a function that does what you describe - f(x) = 1/x2.

\lim_{x \to 0} \frac{1}{x^2}~=~\infty

In one sense, the limit does not exist, because infinity is not a number in the reals. What this limit is saying is that the closer x gets to 0 (from either side), the larger 1/x2 gets.
 
Jimmy25 said:
This has been bugging for a while and I haven't found an answer.

Say you have a function with a vertical asymptote. This asymptote approaches infinity from both sides.

The limit approaching from either side would be infinity. So would you say the limit is infinity or does not exist?
You can say either one. "Infinity" is not a real number so saying that a limit is "infinity" (or "negative infinity) is just saying that the limit does not exist for a particular reason.
 

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