Is the potential in this quadrupole setup correct?

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The discussion centers on the electric potential of a charged particle in a two-dimensional quadrupole, specifically the formula ψ(x,y,t) = (V/ro)*(x^2 + y^2)*Cos(Ωt) with parameters V = 150 volts, ro = 3mm, and Ω = 500,000 Hz. The participant questions the correctness of the potential, noting that it yields units of Volts*meters instead of the expected Volts. A suggested alternative formula is ψ(x,y,t) = (V/ro)*Sqrt(x^2 + y^2)*Cos(Ωt), which aligns with standard potential definitions. The consensus is to seek clarification from the professor regarding the potential's formulation.

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beardo34
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Hello,

I have a problem where a charged particle is residing in a two dimensional quadrupole where the electric potential is given by ψ(x,y,t) = (V/ro)*(x^2 + y^2)*Cos(Ωt). Where we are supposed to use the values V = 150 volts, ro (which is the distance from the center to one of the surface walls) = 3mm, and Ω = 500,000 Hz.

My question is, is that potential the correct potential? It looks to me like the above potential gives units of Volts*meters instead of the correct units of Volts. Am I confused or should I say something to my professor? (I feel like the potential should be ψ(x,y,t) = (V/ro)*Sqrt(x^2 + y^2)*Cos(Ωt)

I appreciate the help
 
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Looks wrong to me. Ask your professor for clarification.
 
thanks for responding vela
 

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