Is the Product of Hausdorff Spaces Always Hausdorff?

  • Thread starter Thread starter emptyboat
  • Start date Start date
  • Tags Tags
    Product
emptyboat
Messages
28
Reaction score
1
Hello, everyone.

Theorem) If each space Xa(a∈A) is a Hausdorff space, then X=∏Xa is a Hausdorff space in both the box and product topologies.

I understand if a box topology, the theorem holds.
but if a product toplogy, I do not understand clearly.

I think if there are distinct points c,d in X, then Uc, Ud (arbitrary open sets in X contain c, d respectively) are equals Xa except for finitely many values of a, so Uc and Ud are not disjoint.
If I have a mistake, please point out it...
 
Physics news on Phys.org
Start with this: if c and d are different points of X then there is an index a\in A for which the projections of c and d differ. Exploit this value of the index.
 
Thanks a lot, arkajad. I understand it.
if only one coordinate is different, they are disjoint.
 
I'm a bit confused by the conditions on the existence of coordinate basis given by Frobenius's theorem. Namely, let's take a n-dimensional smooth manifold and a set of n smooth vector fields defined on it. Suppose they are pointwise linearly independent and do commute each other (i.e. zero commutator/Lie bracket). That means they span the entire tangent space at any point and since commute, they define a local coordinate basis. What does this mean? Well, starting from any point on the...

Similar threads

Replies
15
Views
3K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 15 ·
Replies
15
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
8
Views
3K
  • · Replies 24 ·
Replies
24
Views
6K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
4
Views
3K
Replies
5
Views
2K