Is the Product of Hausdorff Spaces Always Hausdorff?

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SUMMARY

The theorem states that if each space \(X_a\) (for \(a \in A\)) is a Hausdorff space, then the product space \(X = \prod X_a\) is also a Hausdorff space in both the box and product topologies. The discussion clarifies that in the product topology, distinct points \(c\) and \(d\) in \(X\) can be separated by open sets \(U_c\) and \(U_d\) that differ in only finitely many coordinates. This separation is guaranteed by identifying an index \(a \in A\) where the projections of \(c\) and \(d\) differ, ensuring the open sets are disjoint.

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emptyboat
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Hello, everyone.

Theorem) If each space Xa(a∈A) is a Hausdorff space, then X=∏Xa is a Hausdorff space in both the box and product topologies.

I understand if a box topology, the theorem holds.
but if a product toplogy, I do not understand clearly.

I think if there are distinct points c,d in X, then Uc, Ud (arbitrary open sets in X contain c, d respectively) are equals Xa except for finitely many values of a, so Uc and Ud are not disjoint.
If I have a mistake, please point out it...
 
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Start with this: if c and d are different points of X then there is an index a\in A for which the projections of c and d differ. Exploit this value of the index.
 
Thanks a lot, arkajad. I understand it.
if only one coordinate is different, they are disjoint.
 

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