Is the RLC Circuit in Resonance?

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SUMMARY

The discussion centers on the resonance of an RLC circuit, specifically addressing the relationship between frequency and time period. The resonant frequency, denoted as f0, is calculated using the formula f0 = 1/T, where T is the time period observed in the graph. With a time period of 4 ms, the resonant frequency is determined to be 250 Hz. Additionally, the discussion clarifies that resonance occurs when the current and voltage reach their peaks simultaneously, indicating they are in phase.

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  • Familiarity with sine waveforms and their properties
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Loke
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-Is the RCL circuit in resonant? Explain
-Given that C is equal to 2X10-3F, find inductance, L.

problems:
-Is fo equal to 1...because the maximum value in the graph at t=1?
-from the graph,how to know that the graph is resonant or not?...can i say that because the current and the voltage reaches it peaks at the same instant ...that's y they are in phase = resonant ?

please advice.
 

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--- f0 is not equal to 1. It is the reciprocal of time at which the sine waveform repeats itself. From graph you can see the time period is 4 ms.

--- your way of thinking is correct about a resonant circuit.
 
you meant the resonance frequency,fo = 1/T = 1/(4x10^-3) =250s^-1 ?
 

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