MHB Is the sequence $(X_n)$ of $L^1$ random variables uniformly integrable?

  • Thread starter Thread starter Euge
  • Start date Start date
  • Tags Tags
    2017
Click For Summary
The discussion revolves around the conditions under which the sequence of $L^1$ random variables $(X_n)$ is uniformly integrable. It highlights two key conditions: the expectation $\Bbb E[f(|X_n|)]$ must be uniformly bounded, and the function $f(x)$ must satisfy the property that $\dfrac{f(x)}{x}\to \infty$ as $x\to \infty$. The problem is part of a weekly challenge, and due to its difficulty, the deadline for submissions has been extended. No solutions have been provided yet, prompting the poster to share their own solution. The focus remains on proving the uniform integrability of the sequence based on the stated conditions.
Euge
Gold Member
MHB
POTW Director
Messages
2,072
Reaction score
245
Here is this week's POTW:

-----
Let $(X_n)$ be a sequence of $L^1$ random variables on a probability space $(\Omega, \Bbb P)$. Let $f$ be a continuous, nondecreasing function from $[0,\infty)$ onto itself such that

1. $\Bbb E[f(|X_n|)]$ is uniformly bounded

2. $\dfrac{f(x)}{x}\to \infty$ as $x\to \infty$

Show that $(X_n)$ is uniformly integrable.
-----

Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
 
Physics news on Phys.org
Due to the difficulty some may have had with this problem, I'm extending the deadline one more week.
 
No one answered this week's problem. You can read my solution below.
Set $M = \sup_{m\in \Bbb N} E[f(\lvert X_n\rvert)]$. Given $\epsilon > 0$, choose $\delta > 0$ such that for all $x$, $x \ge \delta$ implies $f(x) > \frac{x}{\epsilon}$. For all $n\in \Bbb N$,

$$E[\lvert X_n\rvert I_{\lvert X_n\rvert \ge \delta}] \le E[\epsilon f(\lvert X_n\rvert)I_{\lvert X_n\rvert \ge \delta}] \le \epsilon M$$

Since $\epsilon$ was arbitrary, $(X_n)$ is uniformly integrable.