Is the system in translational equilibrium?

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Homework Help Overview

The discussion revolves around the concept of translational equilibrium in a mechanical system involving a wrench and a nut. Participants are exploring the conditions under which the system may or may not be in equilibrium based on the forces applied and the motion of the center of mass.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster questions whether the system is in translational equilibrium and if a reaction force exists at the nut to achieve a net resultant force of zero. Other participants raise additional questions about the motion of the center of mass and the conditions for the system to remain in equilibrium.

Discussion Status

Participants are actively engaging with the concepts, with some expressing confusion and seeking clarification. There is a recognition that if the system is not free to move, a reaction force at the nut may be necessary, indicating a productive exploration of the topic.

Contextual Notes

Some participants express uncertainty about the clarity of the original question and the implications of the system's movement on equilibrium, suggesting that assumptions about motion and forces are under examination.

Oerg
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Ok, I need to clear a little conceptual misunderstanding and I hope some of you will be kind enough to help me.

Consider a mechanic turning a wrench about a nut. He exerts a force that is perpendicular to the wrench.

Is the system in translational equilibrium? Is there a reaction force at the nut such that it will give a net resultant force of zero ?
 
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any help? :confused::cry:
 
is there something wrong with my question :sigh: last and final bump
 
I too have two questions :-)

Whether the center of mass of the wrench remains stationary?

Whether the system with the nut is free to move and still remains in equilibrium?
 
ok,

centre of mass of wrench does not remain stationary

System is free to move and to display translational motion.

Oh, I get it, if the system is not free to move, that means that there will be a reaction force at the nut correct??
 

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