Is There a Defined Method for Calculating Quaternion Derivatives?

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The discussion revolves around the existence and calculation of quaternion derivatives, particularly in the context of physics applications. The initial inquiry questions whether a quaternion derivative can be defined without a numerical representation of the quaternion unit k. Participants clarify that while the concept of a quaternion derivative is less established than in complex analysis, it can be approached through the Cayley-Dickson doubling form and by adapting complex functions. The conversation highlights the need for quaternionic generalizations of Cauchy-Riemann equations to establish meaningful derivative calculations. Ultimately, the thread provides insights into the methodology for computing quaternionic derivatives and references additional resources for further exploration.
Topolfractal
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I am trying to work out some basic aspects in the theory of quaternions for some work in physics I'm doing. I have went through complex analysis and saw that the only way division ( and hence the derivative) could be defined was through a numerical definition of (i). My question is does there exist a notion of a quaternion derivative even without a numerical definition of ( k, quaternion part) ? I have some pieces of a possible answer, but am far away from meaningful mathematical consistency. I would greatly appreciate if someone would push me in the right direction.
 
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Topolfractal said:
I am trying to work out some basic aspects in the theory of quaternions for some work in physics I'm doing. I have went through complex analysis and saw that the only way division ( and hence the derivative) could be defined was through a numerical definition of (i).
?
Division of complex numbers is done by multiplying by 1 in the form of the complex conjugate of the divisor over itself. This produces a real number in the denominator. What do you mean by "numerical definition of (i)"?

Also, what do you mean by the derivative here? Are you talking about a function f whose domain and range are the complex numbers?
Topolfractal said:
My question is does there exist a notion of a quaternion derivative even without a numerical definition of ( k, quaternion part) ? I have some pieces of a possible answer, but am far away from meaningful mathematical consistency. I would greatly appreciate if someone would push me in the right direction.

I suppose you could have a function whose domain and range are quaternions. I have never heard about the derivative of such a function, but that doesn't mean that no one has done any work in this direction. To calculate a derivative you would need to use the difference quotient definition of the derivative, which entails doing division. This wikipedia article talks about the conjugate and the reciprocal of a quaternion - https://en.wikipedia.org/wiki/Quaternion
 
That helps out a lot thank you. What I mean is that the complex conjugate and complex number become real under multiplication, because we know precisely what i=sqrt(-1) and how to multiply it. This is coming though from a person who heard about quaternions but not researched them thoroughly, so I could be completely wrong.
 
Topolfractal said:
That helps out a lot thank you. What I mean is that the complex conjugate and complex number become real under multiplication, because we know precisely what i=sqrt(-1) and how to multiply it.
I think I know what you mean, but that's not what you're saying. A complex number and its conjugate don't become real - their product is real, due to the way multiplication of complex numbers is defined (which includes the definition of i * i = -1).
Topolfractal said:
This is coming though from a person who heard about quaternions but not researched them thoroughly, so I could be completely wrong.
 
Thank for the clarifications and after skimming the article I now know where I went wrong and know now about Hamiltonian's insight. It's all making sense now.
Mark44 said:
I think I know what you mean, but that's not what you're saying. A complex number and its conjugate don't become real - their product is real, due to the way multiplication of complex numbers is defined (which includes the definition of i * i = -1).
Thank you that's where I was trying to go, but just couldn't phrase it right.
 
The best and simplest way to compute a quaternionic derivative is as follows. We represent a quaternion argument p = x+y⋅i+z⋅j+u⋅k (i,j,k are basic quaternion units; "⋅" is the quaternion multiplication) and a quaternion-differentiable (holomorphic) function of that argument ψ(p) = ψ1(x,y,z,u)+ψ2(x,y,z,u)⋅i+ψ3(x,y,z,u)⋅j+ψ4(x,y,z,u)⋅k in the Cayley–Dickson doubling form: p = a+b⋅j, where a´= x+y⋅i ; b = z+u⋅i and ψ(p)=ψ(a,b)=Φ1(a,b)+Φ2(a,b)⋅j, where Φ1(a,b)=ψ1(a,b)+ψ2(a,b)⋅i and Φ2(a,b)=ψ3(a,b)+ψ4(a,b)⋅i. Each expression for ψ(p) is initially to be obtained from a complex function of the same kind by means of the direct replacement of a complex variable with a quaternion variable in the expression for the complex function. For example, ψ(p)=p-1. Just as a complex- holomorphic function satisfies Cauchy-Riemann's equations in complex analysis, a quaternion- holomorphic function satisfies the following quaternionic generalization of Cauchy-Riemann's equations:
(1) ∂aΦ1 = ∂b×Φ2×, (2) ∂aΦ2 = - ∂b×Φ1×,
(3) ∂aΦ1 = ∂bΦ2, (4) ∂a×Φ2 = - ∂b×Φ1
after doing a = a× = x,​
where the complex conjugation is denoted by × and the partial differentiation with respect to some variable s is denoted by ∂s. For example, by ∂b×Φ2× is denoted the partial derivative of the complex conjugate of a function Φ2 with respect to the complex conjugate of a complex variable b. Firstly, we compute the partial derivatives of functions Φ1, Φ2, Φ1×, Φ2× (with respect to variables a, b, a×, b×); secondly, we put a = a× =x in the computed expressions of partial derivatives; and thirdly, we check whether equations (1) - (4) hold. One of the formulae to compute the first quaternionic derivative of the quaternion-holomorphic function is the following:
ψ(p)(1) = (∂aΦ1 + ∂a×Φ1) + (∂aΦ2 + ∂a×Φ2)⋅j .​

Higher derivatives of quaternion-holomorphic functions can be computed analogically and they are holomorphic like the first derivative.
For details and examples I refer to http://vixra.org/abs/1609.0006
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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