Is There a Formula for Summing 1/n Using the Digamma Function?

  • Context: MHB 
  • Thread starter Thread starter mathmaniac1
  • Start date Start date
  • Tags Tags
    Formula Summation
Click For Summary
SUMMARY

The discussion centers on the summation of the series sigma(1/n) and its relationship with the digamma function. It is established that there is no closed formula for the infinite series, which is divergent. However, the finite series can be expressed in closed form using the nth Harmonic number, H_n, and the digamma function, φ(n), where φ(n) is defined as the derivative of the logarithm of the factorial function. The approximation for large n is given by γ + ln(n), where γ is the Euler-Mascheroni constant.

PREREQUISITES
  • Understanding of infinite and finite series
  • Familiarity with the Harmonic number, H_n
  • Knowledge of the digamma function, φ(x)
  • Basic calculus, specifically differentiation and logarithmic functions
NEXT STEPS
  • Research the properties and applications of the digamma function
  • Explore the concept of Harmonic numbers and their significance in mathematics
  • Study the divergence of infinite series and its implications
  • Learn about difference equations and their role in summation formulas
USEFUL FOR

Mathematicians, students studying calculus and series, and anyone interested in advanced mathematical concepts related to summation and series analysis.

mathmaniac1
Messages
158
Reaction score
0
sigma(1/n)

Is there a formula for it?
 
Physics news on Phys.org
mathmaniac said:
sigma(1/n)

Is there a formula for it?

Also note that the infinite series is divergent, and so that can not possibly have a closed form.
 
Prove It said:
Also note that the infinite series is divergent, and so that can not possibly have a closed form.

The above statement is not quite correct as

sigma n = n(n+1)/2 is divergergent but it has a colsed form
 
kaliprasad said:
The above statement is not quite correct as

sigma n = n(n+1)/2 is divergergent but it has a colsed form

The FINITE series has a closed form. The INFINITE series does not. There is nothing wrong with what I said.
 
Why not a formula f(n) such that f(n)-f(n-1)=1/n
Why isn't it possible?
 
Prove It said:
The FINITE series has a closed form. The INFINITE series does not. There is nothing wrong with what I said.

I am sorry about my statement. I I meant closed form for the finite sum and then as n tends to infinite. My due apologies
 
mathmaniac said:
Why not a formula f(n) such that f(n)-f(n-1)=1/n
Why isn't it possible?

It is neither algebraically possible to obtain a homogeneous difference equation by symbolic differencing, nor to find an elementary particular solution to attempt the method of undetermined coefficients.

So what we do is write:

$$\sum_{k=1}^n\frac{1}{k}=H_n$$

where $H_n$ is the $n$th Harmonic number - Wikipedia, the free encyclopedia.
 
Is it possible to figure out whether an inductive formula exists for sigma something?
 
  • #10
Do you find a pattern from which you can infer an induction hypothesis?
 
  • #11
Looking for a pattern is not easy,how do you know when to stop looking and conclude there is no formula?
I think most series including reciprocals have no formulae,but some have and is it possible to check?
 
  • #12
In...

http://mathhelpboards.com/discrete-mathematics-set-theory-logic-15/difference-equation-tutorial-draft-part-i-426.html#post2494

... it has been demonstrated that is...

$\displaystyle \sum_{k=1}^{n} \frac{1}{k} = \phi (n) + \gamma\ (1)$

... where $\phi(*)$ is the digamma function, defined as...

$\displaystyle \phi(x) = \frac{d}{d x} \ln x!\ (2)$

... being...

$\displaystyle x! = \int_{0}^{\infty} t^{x}\ e^{- t}\ dt\ (3)$

Kind regards

$\chi$ $\sigma$
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K