Is There a Fundamental Theorem of Calculus for Squared Derivatives?

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SUMMARY

The discussion centers on the existence of a fundamental theorem of calculus (FTC) analog for squared derivatives, specifically examining the integral \(\int_a^b \left( \frac{df}{dx} \right)^2 dx\). Participants confirm that, unlike the standard FTC, which states \(\int_a^b \frac{df}{dx} dx = f(b) - f(a)\), there is no established theorem for the squared derivative case. The conversation highlights the lack of a definitive answer or widely accepted theorem addressing this specific integral form.

PREREQUISITES
  • Understanding of calculus fundamentals, including integrals and derivatives.
  • Familiarity with the Fundamental Theorem of Calculus.
  • Knowledge of mathematical notation and expressions.
  • Basic concepts of squared functions in calculus.
NEXT STEPS
  • Research the implications of squared derivatives in calculus.
  • Explore advanced calculus topics related to integral transformations.
  • Investigate potential analogs or extensions of the Fundamental Theorem of Calculus.
  • Study mathematical literature on the properties of integrals involving higher-order derivatives.
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Mathematics students, educators, and researchers interested in advanced calculus concepts, particularly those exploring the properties of derivatives and integrals.

Bruno Tolentino
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Fundamental theorem of calculus:[tex]\int_a^b \frac{df}{dx} dx = f(b) - f(a)[/tex]
All right? Everybody knows...

BUT, BUT, exist some analog of the FTC for this case:

[tex]\int_a^b \left( \frac{df}{dx} \right)^2 dx = ?[/tex]

Hum?
 
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Bruno Tolentino said:
Fundamental theorem of calculus:[tex]\int_a^b \frac{df}{dx} dx = f(b) - f(a)[/tex]
All right? Everybody knows...

BUT, BUT, exist some analog of the FTC for this case:

[tex]\int_a^b \left( \frac{df}{dx} \right)^2 dx = ?[/tex]
Not that I'm aware of.
 
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