Is there a mistake in the second equation of (5.139)?

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SUMMARY

The discussion identifies a mistake in the second equation of (5.139) derived from the Euler-Lagrange equation. The left-hand side (LHS) is calculated as ##mr^2\ddot{\theta}-mr\dot{x}(-\sin\theta)\dot{\theta}-mr\ddot{x}\cos\theta##, while the right-hand side (RHS) is ##mgr\sin\theta##. The participant asserts that a ##\theta##-dependent term was neglected during differentiation, which is crucial for accurate equation formulation. This oversight leads to the final equation being expressed as ##r\ddot{\theta}+\dot{x}\sin\theta\dot{\theta}-\ddot{x}\cos\theta=g\sin\theta##.

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I believe there is a mistake in the second equation of (5.139).

Screen Shot 2016-08-05 at 2.39.45 am.png


The equation is obtained from (5.138) using the Euler-Lagrange equation
##\frac{d}{dt}\frac{\partial L}{\partial\dot{\theta}}=\frac{\partial L}{\partial\theta}.##

LHS##\,\,=\frac{d}{dt}\frac{\partial L}{\partial\dot{\theta}}=\frac{d}{dt}(mr^2\dot{\theta}-mr\dot{x}\cos\theta)##
##=mr^2\ddot{\theta}-mr\dot{x}(-\sin\theta)\dot{\theta}-mr\ddot{x}\cos\theta\,\,\,\,\,\,\,\,\,\,## (Note that ##\dot{r}## terms are ignored.)

RHS##\,\,=mgr\sin\theta##

Equating LHS and RHS, and dividing by ##m## and ##r##, we have
##r\ddot{\theta}+\dot{x}\sin\theta\dot{\theta}-\ddot{x}\cos\theta=g\sin\theta##.

Am I right?
 
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There's a ##\theta##-dependent term that you have forgotten to differentiate inside the parentheses.
 
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